The answer is a, because the absolute value of x(the actual weight of the product) minus the target weight of 18.25 needs to be greater that the target weight difference of .36 so that it is outside the range. So basically, any number outside of the range will be correct.You can plug in number that you know are in/ out of the acceptable range of numbers for this problem in.
|18.62-18.25|>.36
.37>.36
18.62 is not in range.
Answer:
The money he can save by buying them at Big 5 is $76.80.
Step-by-step explanation:
Given:
Footballs sell for $27.99 each at Sporting Goods.
Footballs sell for $21.59 each at Big 5.
The coach buys a dozen footballs.
Now, to find the amount he save by buying them at Big 5.
So, first we find the cost of footballs at Sporting Goods and at Big 5.
1 Dozen = 12 pieces.
Thus, the cost of footballs at Sporting Goods =
And, the cost of footballs at Big 5 =
Now, to get the amount coach can save by buying them at Big 5, we subtract both the cost as the cost of Sporting Goods is more than the Cost of Big 5:
The amount coach can save by buying them at Big 5 =
Therefore, the amount he can save by buying them at Big 5 is $76.80.
Answer:
they need to sell 15,000 because 42 percent of 15,00 is 6,300+2500=800
the inequality should be. 2500+0.42s≥8,800
and the number line should have a closed point on 15,000 with the line pointing to the right
I think that the answer is quadratic
Answer:
The absolute value graph below does not flip.
Step-by-step explanation:
New graphs are made when transformed from their parents graphs. The parent graph for an absolute value graph is f(x) = |x|.
The equation used for a new graph transformed from the parent graph is in the form f(x) = a |k(x - d)| + c.
"a" shows vertical stretch (a>1) or vertical compression (0<a<1), and <u>flip across the x-axis if "a" is negative</u>.
"k" shows horizontal stretch (0<k<1) or horizontal compression (k>1), and <u>flip across the y-axis if "k" is negative</u>.
"d" shows horizontal shifts left (positive number) or right (negative number).
"c" shows vertical shifts up (positive) or down (negative).
The function f(x)=2|x-9|+3 has these transformations from the parent graph:
a = 2; Vertical stretch by a factor of 2
k = 1; No change
d = 9; Horizontal shift right 9 units
c = 3; Vertical shift up 3 units
Since neither "a" nor "k" was negative, there were no flips, <u>also known as reflections</u>.
