Answer:
$150
Explanation:
Calculation of how much income that Gramps will recognize on the first payment.
Since joint survivor annuity has 23.1 as the annual return multiple .
Calculation for Expected return
Expected return =Annual payment *Return multiple
($500*12) =$6,000
$6,000×23.1
=$138,600
Therefore :
$97,020/$138,600
=0.7×100
=70%
The 70% of each of the payment will be the return of capital while the 30%(100%-70%) will be the income.
Hence the first payment be:
30%×500
=$150
Therefore the amount of income that Gramps will recognize on the first payment will be $150
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
Juan should call Violet and discuss the issue with her. The two of them should reach an agreement on how they will be taking care of the office on a daily basis. Each of them should be responsible for cleaning and organizing the office daily. In case the two of them are always too busy to clean up, then, they can employ a cleaner, who will be cleaning for them daily and the two of them will contribute to pay the cleaner.
Answer: The answer is $2,759.22
Explanation: From the question above, we have:
September 1st to January 1st is 4 months, this is 1/3 of a year which means that the student will earn:
=> 9/3 = 3%
3% interest for the money that is saved is the savings account. So the student must put in at least:
x + 3%x = 1400
x + 0.03x = 1400
1.03x = 1400
x = 1400 / 1.03
x = 1,359.22
Therefore, if the student saves $1,359.22 in the savings account By September 1st, she will have $1400 by January 1st.
Also, the student needs to make $1400 for the first semester. So overall she will need to make:
1,400 + 1,359.22 = $2,759.22 during the summer in order to ensure that she will have enough money to pay for both semesters.
Answer:
Cost of Good Sold Using Fifo $40,570
Ending inventory using Fifo $3,600
Ending inventory Using Specific Identification can not be calculated as the total sales (555) exceeds the available inventory (510)
Explanation:
