Answer:
answer is (3,7)
Step-by-step explanation:
a) Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of equations
b) since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of equation
In order to show if the given point corresponds to the given function, we will have to substitute the value of x into the function to see if we will have its corresponding y-value
For the point (-0.8, -0.6), substitute x = -0.8 into both functions as shown:
f(x) = 2x + 1
f(-0.8) = 2(-0.8) + 1
f(-0.8) = -1.6 + 1
f(-0.8) = -0.6
Simiarly;
y = -3(-0.8)- 3
y = 2.4 - 3
y = -0.6
Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of equations
For the point (1/3, 2), substitute x = 1/3 into both functions as shown:
x = (y+2)/2
x = (2+2)/2
x = 4/2
x = 2
Simiarly;
x + 2 = 3
x = 3-2
x = 1
Since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of equations
Learn more on systems of equation here: brainly.com/question/847634
It can somteimes be one of the data values. When there's an odd set of numbers, the median will always be one of the data values. When there's a even set of numbers, the median will sometimes be one of the data values.
Even:
2, 3, 4, 5, 6, 7
Now, we need to find the number between 4 and 5, which is 4.5, 4.5 doesn't show up in the data set.
2,3, 5, 5, 6, 7
The middle of 5 and 5 is 5 since it's the same number. 5 does show up in the data set.
So, the median sometimes is one of the data values.
Answer:
(2, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
2x + y = 5
3x - 2y = 4
<u>Step 2: Rewrite Systems</u>
<em>Manipulate 1st equation</em>
- [Subtraction Property of Equality] Subtract 2x on both sides: y = 5 - 2x
<u>Step 3: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [2nd Equation]: 3x - 2(5 - 2x) = 4
- [Distributive Property] Distribute -2: 3x - 10 + 4x = 4
- [Addition] Combine like terms: 7x - 10 = 4
- [Addition Property of Equality] Add 10 on both sides: 7x = 14
- [Division Property of Equality] Divide 7 on both sides: x = 2
<u>Step 4: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [Modified 1st Equation]: y = 5 - 2(2)
- Multiply: y = 5 - 4
- Subtract: y = 1
Answer:
The surface area is 270in units squared
