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1 year ago

Balance each reaction and write its reaction quotient, Qc:(b) POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Chemistry

1 answer:

Komok [63]1 year ago

4 0

When we balance the given equation

POCl₃(g) ⇄ PCl₃(g) + O₂(g)

We will get

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

Solution:

Balancing the given equation

POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of O

2POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of P and Cl

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

We get the balanced equation

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

The reaction quotient will be

Qc = [product] / [reactant]

Qc = [PCl₃(g) + O₂(g)] / [POCl₃(g) ]

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A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. what is the partial pressure o

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Hello!

We have the following statement data:

Data:
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As the percentage is the mole fraction multiplied by 100:

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$X_{ O_{2} } = \frac{P}{100}$
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To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:

In relation to $O_{2}$ :

$\frac{P O_{2} }{P_{total}} = X_O_{2}$
$\frac{P O_{2} }{800} = 0.4$
$P_O_{2} = 0.4*800$
$\boxed{\boxed{P_O_{2} = 320\:mmHg}}\end{array}}\qquad\quad\checkmark$

Answer:
b. 320.0 mm hg

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