When we balance the given equation
POCl₃(g) ⇄ PCl₃(g) + O₂(g)
We will get
2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)
Solution:
Balancing the given equation
POCl₃(g) ⇄ PCl₃(g) + O₂(g)
Balancing the number of O
2POCl₃(g) ⇄ PCl₃(g) + O₂(g)
Balancing the number of P and Cl
2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)
We get the balanced equation
2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [PCl₃(g) + O₂(g)] / [POCl₃(g) ]
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