The polyatomic nitrate ion (NO3−) is present in both the products and the reactants of the chemical equation shown below.
1 answer:
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Answer:
5.95g
Explanation:
1 = 1000 mL
∴ 100 mL = 100 ÷ 1000 = 0.1
Volume = <u>0.1 </u><u />
Concentration = <u>0.5 M</u>
Concentration =
0.5 =
No. of moles = 0.5 x 0.1 = <u>0.05 moles</u>
No. of moles =
Mass in 1 mole of KBr = 39 + 80 = 119g (39 is the mass of potassium and 80 is the mass of bromine)
0.05 =
x = 119 × 0.05 = 5.95g
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