Answer:
Their melting and boiling points of alkanes are relatively low. The higher the molecular weight (the greater the number of carbons), the higher the boiling point.
Full question:
The IUPAC name for CH3CH2C≡CCH3 is:
Answer:
2-pentyne
Explanation:
To name hydrocarbons, you first you have to identify the longest carbon chain. There are 5 carbons in this chain, so we know the name is "pent".
You then have to identify the presence of any double or triple bonds. If double bonds, it is an alkene, if triple bonds, it is an alkyne. In this case there is a triple bond, so we know the hydrocarbon is pentyne.
You then number the chain to give the lowest number to the triple bond. It could either be 4 (countnig carbons from left to right) or 2 (from right to left). Therefore, the answer is 2-pentyne.
Trick question: you just stated everything in the beakers.
Answer b) a to c would be considered one wavelength.
Answer:
0.0140 M H₂C₆H₆O₆.
Explanation:
- We should mention the relation: <em>Ka = α²C,</em>
Where, Ka is the dissociation constant of the acid.
α is the degree of ionization of the acid.
C is the concentration if the acid.
<em>The percent of ionization (α %) = α x 100.</em>
α = √Ka/C
∴ α is inversely proportional to the concentration of the acid.
<em>So, the acid with the lowest concentration has the greatest percent ionization.</em>
