The strength of an acid increases if the stability of conjugate base increases
The stability of a conjugate base increases with the presence of electron with drawing group (electronegative group)
Thus more the electronegativity of an atom attached to a carboxylic acid higher the strength of acid
In these examples CH3CH2CH2CF2CH2COOH contains to electronegative flourine atoms which stabilizes the conjugate base hence this will be the strongest acid among the given acids
<em>Answer:</em> 20 m/min east
<em>Explanation:</em> The speed is distance divided by time
distance between start-point and end-point = 100 meters
<em>time to cover the distan</em>ce = 5 minutes
100 m ÷ 5 min = 20 m/min east
y<u>ou have to add east since velocity is the measure of speed and direction and your answer needs to include the direction</u>
1. Find its coordination figure/coordination number of central atom (CF)
Ev = Vallence electron of central atom
Σe = electrons donated from substituents
Terminal O gives 0 electrons, hence Σe = 3 x 0
charge = charge of the compound
2. Find EP (electron pairs) and LP (lone pairs)
LP = CF - EP
3. Draw the skeleton with octet substituents (top right figure)
4. Find formal charge for each atoms (Qf)
5. Write formal charge near atom in skeleton
6. Enjoy
