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1 year ago

1. Describe the process of gene splicing.

Chemistry

1 answer:

AnnyKZ [126]1 year ago

4 0

Answer:

The DNA is cut using special chemicals called restriction enzymes,.

DNA ligase are used to insert genes and other pieces of DNA into plasmids.

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HURRYYY!!!!!!!!!!

vlabodo [156]

Im not sure but i think its 350. I really hope im right

8 0

2 years ago

A lead mass is heated and placed in a foam cup calorimeter containing 40.0 mL of water at 17.0°C. The water reaches a temperatur

lbvjy [14]

Answer: 502 Joules

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 40.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{40.0mL}\\\\\text{Mass of water}=(1g/mL\times 40.0mL)=40.0g$

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$q=m\times c\times \Delta T$

q = heat absorbed by water

$m$ = mass of water = 40.0 g

$T_{final}$ = final temperature of water = 20.0°C

$T_{initial$ = initial temperature of water = 17.0°C

$c$ = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

$q=40.0\times 4.186\times (20.0-17.0)]$

$q=502J$

Hence, the joules of heat were re-leased by the lead is 502

5 0

2 years ago

For the reaction represented by the equation Fe + H2O ® Fe2O3 + H2, how many moles of iron(III) oxide are produced from 285 g of

schepotkina [342]

Balanced equation: 2Fe + 3H2O → Fe2O3 +3H2

Convert g to mols:

285/55.845 = 5.1034 mols

Mole ratio of Iron and Iron (III) Oxide: 2:1

5.1034/2 = 2.5517 mols

8 0

2 years ago

A hot air balloon is filled to 1250 m3 at 27 C. At what temperature will the balloon be filled to 1600 m3 if the pressure remain

SSSSS [86.1K]

Answer:

384.2 K

Explanation:

First we convert 27 °C to K:

27 °C + 273.16 = 300.16 K

With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:

T₁V₂=T₂V₁

Where in this case:

T₁ = 300.16 K

V₂ = 1600 m³

T₂ = ?

V₁ = 1250 m³

We input the data:

300.16 K * 1600 m³ = T₂ * 1250 m³

And solve for T₂:

T₂ = 384.2 K

7 0

2 years ago

Convert 213.62 grams of xenon gas at STP to L.

jolli1 [7]

Answer: The coefficient is 3.645

The exponent is 1

There are 4 significant digits

The rightmost significant figure is 5

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as $5.0\times 10^3$

According to avogadro's law, 1 mole of every gas contains avogadro's number $6.023\times 10^{23}$ of particles, occupy 22.4 L at STP and weighs equal to its molecular mass.

131.29 g of Xe occupy = 22.4 L at STP.

Thus 213.62 g of $Xe$ occupy = $\frac{22.4}{131.29}\times 213.62=36.45L$ at STP.

Scientific notation = $3.645\times 10^1L$

The coefficient is 3.645

The exponent is 1

There are 4 significant digits

The rightmost significant figure is 5

4 0

2 years ago