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2 years ago

How does an atom of tellerium become an ion.

1 answer:

8 0

Answer: Element Tellurium (Te), Group 16, Atomic Number 52, p-block, Mass 127.60. ... defined as being the charge that an atom would have if all bonds were ionic.

What ion does tellurium form?

Te+4

Tellurium, ion (Te4+) | Te+4 - PubChem.

Explanation: Tellurium is a chemical element with the symbol Te and atomic number 52. It is a brittle, mildly toxic, rare, silver-white metalloid.

Tellurium

Tellurium Element - Visual Elements Periodic Table

Discovery date 1783

Discovered by Franz-Joseph Müller von Reichenstein

Origin of the name The name is derived from the Latin 'tellus', meaning Earth.

Allotropes

Tellurium

52127.60

Fact box

Group 16 Melting point 449.51°C, 841.12°F, 722.66 K

Period 5 Boiling point 988°C, 1810°F, 1261 K

Block p Density (g cm−3) 6.232

Atomic number 52 Relative atomic mass 127.60

State at 20°C Solid Key isotopes 130Te

Electron configuration [Kr] 4d105s25p4 CAS number 13494-80-9

ChemSpider ID 4885717 ChemSpider is a free chemical structure database

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If 45.0 mL of ethanol (density = 0.789 g/mL) initially at 8.0 ∘C is mixed with 45.0 mL of water (density = 1.0 g/mL) initially a

strojnjashka [21]

Answer : The final temperature of the mixture is, $22.14^oC$

Explanation :

First we have to calculate the mass of ethanol and water.

$\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 45.0mL=35.5g$

and,

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g$

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.42J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol = 35.5 g

$m_2$ = mass of water = 45.0 g

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $8.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get:

$35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.14^oC$

Therefore, the final temperature of the mixture is, $22.14^oC$

3 0

3 years ago

Shifts in the rock layer locations cannot account for gaps in the rock record<br><br> true or false

vivado [14]

Answer: That would be false because it is the contact between two layers representing a gap in the geologic record, usually from the erosion of the layers which would normally be expected to appear.

Explanation:

Have a good day

I hope this helps if not sorry :(

Stay motivated

4 0

3 years ago

Which statement best describes how an existing theory is often affected by the development of new technology?

grigory [225]

Answer: An existing theory is modified so that it can explain both the old and new observations.

Explanation:

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3 years ago

Which of the following has the greatest influence on the size and force of waves?

svlad2 [7]

Wind speed bc The faster the wind, the longer it blows, or the farther it can blow uninterrupted, the bigger the waves.

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2 years ago

Read 2 more answers

93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0C what would be the volume of this dry gas at STP

Dahasolnce [82]

The volume of the dry gas at stp is calculated as follows

calculate the number on moles by use of PV =nRT where n is the number of moles

n is therefore = Pv/RT
P = 0.930 atm
R(gas contant= 0.0821 L.atm/k.mol
V= 93ml to liters = 93/1000= 0.093L
T= 10 + 273.15 = 283.15k

n= (0.930 x0.093) /(0.0821 x283.15) = 3. 72 x10^-3 moles

At STp 1 mole = 22.4L
what about 3.72 x10^-3 moles

by cross multiplication

volume = (3.72 x10^-3)mole x 22.4L/ 1 moles = 0.083 L or 83.3 Ml

3 0

3 years ago