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Katena32 [7]
3 years ago
5

Helppp me please i’m going to fail

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0
Multiple the top equation by 2 and rearrange so that -7 is equal to the others.
-10x+2y=-14
-3x-2y=-12
——————-
-13x=-26
Divide both by -13
x=2
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How do you subtract fractions with different denominators (I completely forgot)​
Ghella [55]

Answer:

multiply them by a a number that allows the denominators to be the same

Step-by-step explanation:

example

1/2-1/6

I would multiply 1/2 by 3 to get 3/6 which i could then subtract from 1/6

3/6-1/6 = 2/6

6 0
2 years ago
How can you model 8÷2/7
fredd [130]
8÷2/7
8/1÷2/7
8/1*7/2
56/2
28

Hope this helps :)
3 0
3 years ago
PLEASE HELP!!! Trapezoid ABCD was dilated to create trapezoid A'B'C'D'. Which statements are true about the trapezoids? Check al
hichkok12 [17]

Answer:

Option A , B and D are true.

The statement which are true:

The length of side AD is 4 units

The length of side A'D' is 8 units.

The scale factor is, \frac{1}{2}

Step-by-step explanation:

Given in figure trapezoid ABCD;

The coordinates of ABCD are:

A= (-4, 0)

B = (-2, 4)

C = (2,4)

D = (4, 0)

Since, trapezoid ABCD was dilated to create trapezoid A'B'C'D' as shown in figure;

The coordinates of A'B'C'D' are;

A' =(-2, 0)

B'=(-1, 2)

C' = (1, 2)

D' = (2, 0)

First calculate the length of AD

Using Distance formula for any two points i.e,

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Since, A = (-4, 0) and D = (4, 0)

then;

Length of AD =  \sqrt{(4-(-4))^2+(0-0)^2}  = \sqrt{(4+4)^2} =\sqrt{64}=8 units

Therefore, the length of side AD is, 8 units.

Similarly find the length of A'D'.

Where A' = (-2, 0) and D' =(2,0)

Using distance formula:

Length of A'D' = \sqrt{(2-(-2))^2+(0-0)^2} =\sqrt{(2+2)^2}= \sqrt{4^2} = 4

Therefore, the length of side A'D' is, 4 units.

Now, find the slope of CD and C'D'

where C =(2, 4) , D = (4, 0) , C' = (1, 2) and D' =(2,0)

using slope formula for any two points is given by:

Slope = \frac{y_2-y_1}{x_2-x_1}

Slope of CD = \frac{0-4}{4-2} = \frac{-4}{2} = -2

Similarly,

Slope of C'D' = \frac{0-2}{2-1} = \frac{-4}{2} = -2

Since, Sides CD and C'D' have same slope i.e, -2

Scale factor(k) states that every coordinate of the original figure has been multiplied by the scale factor.

  • If k > 1, then the  image is an enlargement.
  • if 0<k< 1, then the image is a reduction.
  • If k = 1, then the figure and the image are congruent.

The rule for dilation with scale factor(k) is;

(x, y) \rightarrow (kx , ky)

To find the scale factor:

A = (-4, 0) and A' = (-2, 0)

(-2, 0) \rightarrow (-4k , 0)

On comparing we ghet;

-4k = -2

Divide -4 both sides we get;

k = \frac{1}{2}

∴ The Scale factor is, k = \frac{1}{2}

Since, k < 1 which implies the image is a reduction.

Therefore, the statements which are true regarding about trapezoids are;

The length of side AD is 4 units

The length of side A'D' is 8 units.

The scale factor is, \frac{1}{2}

6 0
3 years ago
Find the product <br> -12 • (-2) <br><br> A. 10<br><br> B. 24 <br><br> C. -24<br><br> D. -14
svetoff [14.1K]
12 x 2 = 24

When you multiply two negative numbers, the answer will be a positive
When you multiply one negative and one positive, the answer will be negative.


Using that rule:

(-12)(-2) = 24

24 is your answer

hope this helps
6 0
3 years ago
To make a greeting card, Bryce used 1/8 sheet of red paper, 3/8 sheet of green paper, and 7/8 sheet of white paper. How many she
Mashutka [201]
11/8 or 1 3/8 or 1.375
6 0
2 years ago
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