at first the average mass some durians was 3.4kg.when 2 durians were added the aevrage mass of the 2 durians was 1.3kg was added

Question

2 years ago

7

the total avrage of durians became 3.1kg.how many durians were there at first?

1 answer:

LekaFEV [45] · Answer 1 · 2023-07-05T04:13:26+03:00

We conclude that the initial number of durians is 12.

<h3>How many durians were there at first?</h3>

Let's say that initially, we had N durians, such that these N durians have an average mass of 3.4kg.

When 2 durians (with an average mass of 1.3kg) more are added, the new average mass is given by:

(N*3.4kg + 2*1.3kg)/(N + 2)

And we know that the above amount is equal to 3.1kg, then we can write:

(N*3.4kg + 2*1.3kg)/(N + 2) = 3.1kg

Now we can solve this equation for N:

(N*3.4kg + 2.6kg) = 3.1kg*(N + 2)

N*(3.4kg - 3.1kg) = 6.2kg - 2.6kg

N*(0.3kg) = 3.6kg

N = (3.6kg)/(0.3kg) = 12

We conclude that the initial number of durians is 12.

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