Answer:
0
Explanation:
This question involves two genes; A and B. According to the question, two parents are crossed as follows: AABB × Aabb. The parents will produce the following gametes:
AABB- AB, AB, AB, AB
Aabb - Ab, Ab, ab, ab
Using these gametes in a punnet square (see attached image), the offsprings in the following proportion will be produced:
AABb = 4/16 = 1/4
AaBb = 4/16 = 1/4
Therefore, none (0) of the offsprings will resemble the phenotype of the second parent (Aabb).
