Answer:
W=315 x 10⁵ J
Explanation:
Given that
F= 2.5 x 10⁵ N
d= 90 m
K.E.=5.4 x 10⁷ J
We know that work done by all force is equal to the change in kinetic energy
Lets take work done by catapult is W
W + F.d= K.E.
W= 5.4 x 10⁷ - 2.5 x 10⁵ x 90 J
W= (540 - 25 x 9) 10⁵ J
W=315 x 10⁵ J
Complete Question:
Given at a point. What is the force per unit area at this point acting normal to the surface with ? Are there any shear stresses acting on this surface?
Answer:
Force per unit area,
There are shear stresses acting on the surface since
Explanation:
equation of the normal,
Traction vector on n,
To get the Force per unit area acting normal to the surface, find the dot product of the traction vector and the normal.
If the shear stress, , is calculated and it is not equal to zero, this means there are shear stresses.
Since , there are shear stresses acting on the surface.
8.64
×10^4
this is 86400 in scientific notation
Since you are looking for the speed, you need to rearrange the formula which is f = speed / wavelength. That should give you speed = f (wavelength.) All you need to do next is to substitute the value to the following equation. speed = 250 Hz (6.0m) that should leave you with 1500 m/s which is very fast.