Answer:
22600 cm³ (3 s.f.)
Explanation:
Please see the attached picture for the full solution.
Answer:
The reflected resistance in the primary winding is 6250 Ω
Explanation:
Given;
number of turns in the primary winding,
= 50 turns
number of turns in the secondary winding,
= 10 turns
the secondary load resistance,
= 250 Ω
Determine the turns ratio;

Now, determine the reflected resistance in the primary winding;

Therefore, the reflected resistance in the primary winding is 6250 Ω
Answer:
19.3m/s
Explanation:
Use third equation of motion

where v is the velocity at halfway, u is the initial velocity, g is gravity (9.81m/s^2) and h is the height at which you'd want to find the velocity
insert values to get answer
![v^2-0^2=2(9.81m/s^2)(38/2)\\v^2=9.81m/s^2 *38\\v^2=372.78\\v=\sqrt[]{372.78} \\v=19.3m/s](https://tex.z-dn.net/?f=v%5E2-0%5E2%3D2%289.81m%2Fs%5E2%29%2838%2F2%29%5C%5Cv%5E2%3D9.81m%2Fs%5E2%20%2A38%5C%5Cv%5E2%3D372.78%5C%5Cv%3D%5Csqrt%5B%5D%7B372.78%7D%20%5C%5Cv%3D19.3m%2Fs)
Answer:
The intensity will be 1/9 as much.
Explanation:
The intensity of the light or any source is inversely related to the square of the distance.

Now according to the question the distance is increased by three times than,

Therefore,

Therefore the intensity will become 1/9 times to the initial intensity.
Answer:
More reactant forms.
Explanation:
Given reaction is,
⇒
per mole
This is an Exothermic Reaction,(ΔE=-57.3KJper mole)
We know the equilibrium point of all Exothermic reactions moves leftward and more reactant is formed at the equilibrium.
<u>Reason:</u>
As heat is being produced in the reaction the additional heat(57.3KJpermole) can be <u>thought of as a product</u> of the reaction.
So,if you increase the temperature ,you provide heat energy,
(in other words heat energy is given) and hence the concentration of the products increases.
So, with respect to LeChateliers Principle,
As the concentration of products is increased by external means,more of the reactants are produced at the equilibrium of the reaction.
Therefore amount of reactants increases as <u>more reactant forms.</u>