Answer:
TECHNICIAN B
Explanation: Drive shaft is an elongated part of the drive system made of steel of a vehicle that transmits the <em>ENGINE TORQUE to the WHEELS</em> of a vehicle. For proper inspection a technician is expected to completely remove the driveshaft to check all its compactment. It is Cylindrical and usually used for <em>REAR-WHEEL-VEHICLES</em>. Drive shafts are known by different names like propeller shaft,Cardan shaft etc it has different types which range from
<em>One-piece drive shaft
,Two-piece drive shaft to Slip-in-tube drive shaft
.</em>
Answer:
potential energy = mgh
= 400÷1000 × 10× 4÷100
= 0.4 × 10 × 0.04
=4/10 ×10×4/100
= 4/10 × 4/10
=16/100
= 0.16 joules
m1 (400) stretches 4cm
m1 (100g) stretches 1cm
so, m2(800g) stretches 8 cm
potential energy of m2 = mgh
= 800/1000 ×10×8/100
= 0.8 × 0.8
=8/10 ×8/10
= 64/100
=0.64 joules
Ratio of s1 to s2
16/100 ÷ 64/100
= 1:4 ( answer)
The answer is A, genetic factors...conditioning. I just took the test. Good luck!!
Answer:
<h3>
The coefficient of kinetic friction between the puck and the ice is 
0.12</h3>
Explanation:
Given :
Initial speed 
Displacement 
m
From the kinematics equation,
Where 
final velocity, in our example it is zero (
), 
acceleration.
From the formula of friction,
Minus sign represent friction is oppose the motion
Where 
( normal reaction force )
( ∵ 
)
So coefficient of friction,
Therefore, the coefficient of kinetic friction between the puck and the ice is 0.12 .
Answer:
0.0816 kgm/s
Explanation:
From the question,
Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.
P =(M+m)u...................... Equation 1
Where P = initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck
Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg
Substitute these values into equation 1
P = (0.002+0.1)0.8
P = (0.102)0.8
P = 0.0816 kgm/s
