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Olegator [25]
3 years ago
5

Let’s consider several models of the Earth’s radiation properties. In each part, assume that the Earth's radiative output balanc

es the input radiation from the Sun, and that there are no other energy or heat sources. 1) Consider a 'far Earth' (FE) that has an orbital distance 1.6 times farther from the sun, but the same diameter as the real Earth (RE). Assume that both are blackbodies with a uniform temperature. What is the ratio of temperatures between those two planets? (Note: you won't need to look up the Earth-Sun distance or the diameter of the Earth) TFE/TRE=
Physics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

0.391

Explanation:

Since they both have the same diameter, the temperature of both earth's surfaces will be proportional to the solar intensity incident on each surface.

The solar intensity is inversely proportional to the square of their distance.

For true earth Te, distance from the sun is r.

For far Earth Fe, distance from the sun is 1.6r

Solar intensity = power p ÷ area of propagation.

Area of propagation = 4¶r^2 (r is their distances from the sun)

Te = P/(4 x 3.142 x r^2) = p/12.568r^2

TTE is proportional to p/12.568r^2

Fe = p/4¶(1.6r)^2 = p/(4 x 3.124 x 2.56 x r^2) = p/32.174r^2

TFE is proportional to p/32.174r^2

Ratio of TFE/TTE =

p/32.174r^2 ÷ p/12.568r^2

= 32.174 ÷ 12.568 = 0.3906

Approximately 0.391

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ahrayia [7]
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<span>we can define a small charge dq as </span>

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<span>So the electric field can be written as: </span>

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8 0
3 years ago
Circuit A
Licemer1 [7]
By V=IR
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3 0
3 years ago
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How much thermal energy is created when a 3000 kg suv brakes to a stop from 20 m/s on a level road?
JulsSmile [24]

Answer:

b. 600,000 J

Explanation:

Applying the law of conservation of energy,

The thermal energy created = Kinetic energy of the suv.

Q' = 1/2(mv²)............... Equation 1

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From the question,

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3 years ago
A car slows down from speed of 72
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Explanation:

Given parameters:

Initial velocity = 72km/hr

Final velocity  = 0km/hr

Time taken  = 25s

Unknown:

Acceleration = ?

Solution:

To solve this problem, convert km/hr to m/s;

           1000m = 1km

           3600s = 1hr

  72km/hr;

          1km/hr  = 0.278m/s

         72km/hr = 0.278 x 72  = 20.02m/s

Acceleration is the change in velocity divided by the time taken;

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The car  is actually decelerating at a rate of 0.8m/s

5 0
2 years ago
In each of the parts of this question, a nucleus undergoes a nuclear decay. Determine the resulting nucleus in each case.
vaieri [72.5K]

Answer:

(A). The resulting nucleus is Fr.

(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

Explanation:

Given that,

A nucleus undergoes a nuclear decay.

(A). In alpha decay,

We know that,

When the nucleus emit alpha particle then atomic mass of particle reduce by 4 and atomic number reduce by 2.

We need to calculate the resulting nucleus

Using given data

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The resulting nucleus is Fr.

(B). In beta-minus decay,

We know that,

When the nucleus emit beta- minus particle then atomic mass of particle is same and atomic number increase by 1.

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Using given data

^{211}_{83}Bi\Rightarrow ^{211}_{83+1}X

^{211}_{83}Bi\Rightarrow ^{211}_{84}Po

The resulting nucleus is Po.

(C). In beta-plus decay,

We know that,

When the nucleus emit beta- plus particle then atomic mass of particle is same and atomic number decrease by 1.

We need to calculate the resulting nucleus

Using given data

^{22}_{11}Na\Rightarrow ^{22}_{11-1}X

^{22}_{11}Na\Rightarrow ^{22}_{10}Ne

The resulting nucleus is Ne.

(D). In gamma decay,

We know that,

When the nucleus emit gamma particle then atomic mass and atomic number of particle is same.

We need to calculate the resulting nucleus

Using given data

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The resulting nucleus is Tc.

Hence, (A). The resulting nucleus is Fr.

(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

4 0
3 years ago
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