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patriot [66]
4 years ago
12

Scientist have changed the model of the atom.what experimental evidence led them to change from the previous model .

Physics
1 answer:
Thepotemich [5.8K]4 years ago
7 0

Rutherford's model of the atom (ESAAQ) Rutherford carried out some experiments which led to a change in ideas around the atom. His new model described the atom as a tiny, dense, positively charged core called a nucleus surrounded by lighter, negatively charged electrons.

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Hello please help i’ll give brainliest
Masteriza [31]

Answer:

D, the lithosphere. (CRUST AND UPPER MANTLE)

Explanation:

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere. Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest. Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).

Information found on:

<u>https://pubs.usgs.gov/gip/dynamic/tectonic.html#:~:text=A%20tectonic%20plate%20(also%20called,both%20continental%20and%20oceanic%20lithosphere.&text=Continental%20crust%20is%20composed%20of,such%20as%20quartz%20and%20feldspar.</u>

3 0
3 years ago
Read 2 more answers
Consider the three displacement vectors
matrenka [14]

Answer:

Explanation:

\overrightarrow{A} = 3\widehat{i}+3\widehat{j}

\overrightarrow{B} = \widehat{i}-4\widehat{j}

\overrightarrow{C} = -2\widehat{i}+5\widehat{j}

(a)

\overrightarrow{D} =\overrightarrow{A}+\overrightarrow{B}+\overrightarrow{C}

\overrightarrow{D} =\left ( 3+1-2 \right )\widehat{i} +\left ( 3-4+5 \right )\widehat{j}

\overrightarrow{D} =\left 2\widehat{i} +4\widehat{j}

Magnitude of \overrightarrow{D} = \sqrt{2^{2}+4^{2}}

                                                                     = 4.47 m

Let θ be the direction of vector D

tan\theta =\frac{4}{2}

θ = 63.44°

(b)

\overrightarrow{E} = - \overrightarrow{A}-\overrightarrow{B}+\overrightarrow{C}

\overrightarrow{E} =\left ( - 3- 1 -2 \right )\widehat{i} +\left ( - 3 + 4+5 \right )\widehat{j}

\overrightarrow{E} =- \left 6\widehat{i} +6\widehat{j}

Magnitude of \overrightarrow{E} = \sqrt{6^{2}+6^{2}}

                                                                     = 8.485 m

Let θ be the direction of vector D

tan\theta =\frac{6}{-6}

θ = 135°

4 0
4 years ago
When a hypothesis is proven wrong, scientists often begin by revising the . After that, it’s common for scientists to redesign t
Rainbow [258]
1) thesis
2) experiment
3 0
3 years ago
Read 2 more answers
Look at the two wave diagrams. Which best describes the difference between wave A and wave B? Wave A has a greater pitch and fre
stealth61 [152]

Answer:

Correct answer is Wave A has a greater pitch and frequency

Explanation:

To understand the given figure, we should know the definition of wavelength, frequency and pitch

Wavelength

wavelength is defined as distance between two successive wave crests or troughs.

Frequency

Frequency is defined as the number of waves which passes through a given point per second. SI unit of frequency is Hertz.

Pitch

our ear understand the frequency of a sound wave as pitch. A a lower frequency sound has a lower pitch and a higher frequency sound has a higher pitch.

In given figure Wave A has lower wavelength and higher frequency so it have higher pitch than wave B.

4 0
4 years ago
Read 2 more answers
Consider massive gliders that slide friction-free along a horizontal air track. Glider A has a mass of 1 kg, a speed of 1 m/s, a
mamaluj [8]

Answer:

0.167m/s

Explanation:

According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.

Given momentum = Maas × velocity.

Momentum of glider A = 1kg×1m/s

Momentum of glider = 1kgm/s

Momentum of glider B = 5kg × 0m/s

The initial velocity of glider B is zero since it is at rest.

Momentum of glider B = 0kgm/s

Momentum of the bodies after collision = (mA+mB)v where;

mA and mB are the masses of the gliders

v is their common velocity after collision.

Momentum = (1+5)v

Momentum after collision = 6v

According to the law of conservation of momentum;

1kgm/s + 0kgm/s = 6v

1 =6v

V =1/6m/s

Their speed after collision will be 0.167m/s

6 0
3 years ago
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