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rewona [7]
2 years ago
13

1. Solve 16+14÷2+3⋅5−11

Mathematics
1 answer:
tiny-mole [99]2 years ago
6 0

Answer:

1. 27

2.6

Step-by-step explanation:

1.

remember the priorities of operations :

1. brackets

2. exponents

3. multiplications and divisions

4. (and truly last) additions and subtractions

so,

16 + 14÷2 + 3×5 - 11 =

16 + 7 + 15 - 11 = 23 + 4 = 27

2.

5 coins are tossed at the same time.

each coin has a result (head or tail).

but the observed event is the sum of all tails that show when tossing the 5 coins.

so, the possible outcomes are

0 tails

1 ...

2 ...

3 ...

4 ...

5 tails

so, in total, 6 different possible outcomes.

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dem82 [27]

Answer: mKLJ = 60ᴼ

Step-by-step explanation:

MLO and KLJ are vertical angles, which means their measures are congruent.

3 0
3 years ago
How to write (-6 '-5) and (3'1) in slope intercept
n200080 [17]

Answer:

You would first put it into point slope form which is (y-y_1)=m(x-x_1). Then you would solve for y.

8 0
4 years ago
Please help. Brainliest for the best explanation.
Virty [35]
Explanation of what exactly
5 0
4 years ago
The length of a iron-sheet and copper-sheet is 672 cm and 960 cm respectively.what will be the length of the highest piece of eq
marissa [1.9K]
In order to calculate the length of highest piece, You need to calculate the Greatest common divisor of 672 & 960 which is 96

So, the length of highest piece would be 96 cm

Now, Number of pieces of Iron-sheet = 672 / 96 = 7
Number of pieces of Copper-sheet = 960 / 96 = 10

Hope this helps!
8 0
3 years ago
Read 2 more answers
Write a pair of numbers such that the value of the 7 in the first number is 1000 times the value of the 7 in the second number,
telo118 [61]

<u>Answer-</u>

As infinitely many such possible number pairs can be formed, one of the instances of such pair would be (37000 and 307).

<u>Solution-</u>

Suppose the former one is aaaaa and the later one is bbbbb.

The value of 7 in the former is 1000 times greater than in the later, so let's make it 7000 and 7.

Then the numbers will be in the following form,

a7aaa and bbbb7

Again, the value of 3 in the former is 100 times greater than in the later.

Then the numbers will be in the following form,

37aaa and bb3bb7

Substituting all the a's and b's by 0,

we get, 37000 and 307 is a possible set. Replacing 0 with any number from 1-9, will yield another number pair which will satisfy the conditions.


6 0
3 years ago
Read 2 more answers
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