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Viefleur [7K]
2 years ago
14

If the potassium atoms could be lined up in a row, how many of them would it take to make a 1.00 ft row of potassium atoms?

Chemistry
1 answer:
LiRa [457]2 years ago
6 0

If the potassium atoms could be lined up in a row, it would take to make a 1.00 ft row of potassium atoms is 5.45 × 10⁻⁸.

Potassium atom is represented by K with atomic number 19. It is a silvery white metal.

Given,

Radius = 280pm = 280 × 10⁻¹²m

Diameter = 2radius = 560× 10⁻¹²m = 560pm

We know that,

1 feet = 0.305m

So, number of potassium atoms that fits into the row,

1 feet = 0.305/560 × 10⁻¹²

1 feet = 5.45 × 10⁻⁸

Hence, it takes 5.45 × 10⁻⁸ atoms of potassium to make a 1 feet row.

Learn more about Potassium here, brainly.com/question/13321031

#SPJ9

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The inner core is the Earth's "interior".

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6 0
3 years ago
What is the ratio of hydrogen atoms (h) to oxygen atoms (o) in 2 l of water? enter the simplest whole number ratio in order of h
KiRa [710]

Answer:- 2,1

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Hence, the answer is 2,1.

4 0
3 years ago
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During which change of state would the volume of a substance increase the most?
Mademuasel [1]

Answer:

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Explanation:

8 0
3 years ago
Ammonia, nh3, is a weak base with a kb = 1.8 x 10-5. in a 0.8m solution of ammonia, which has a higher concentration: ammonia (n
insens350 [35]
Answer is: concentration ammonia is higher than concentration of ammonium ion.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,8 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,8 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
0,000018 = x² /  0,8 mol/L - x.
solve quadratic equation: x = c(NH₄⁺) = 3,79·10⁻³ mol/L.
7 0
3 years ago
A student titrated a 1.0115 g sample of potassium hydrogen phthalate (hkc8h4o4 204.2285g/mol with sodium hydroxide. the initial
melomori [17]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
first determine the equation. KHP is a monoprotic acid, so it reacts with NaOH in a 1:1 ratio. 

<span>a) HKC8H4O4 + NaOH → NaKC8H4O4 + H2O </span>

<span>This allows you to calculate the molarity of NaOH, from the equation V1M1n2 = V2M2n1 </span>

<span>Molarity times volume will give you the number of moles of acid. You can work this out by dividing the mass used by the molar mass. For this question, you will have 1.0115/204.2285 moles KHP, so this value can be substituted for V1M1 in the equation. You need 38.46 mL of NaOH to titrate all the acid, so this will be V2. Now you find M2. </span>

<span>b) 1.0115/204.2285 × 1 = 38.46 × M2 × 1, so M2 = 0.0001288M </span>

<span>Now go on to part 3. Here, you use a similar calculation. The acid and base react in a 1:1 ratio, so n1 = n2 = 1. M2 = 0.1905 and V2 = 25.62. V1M1 will be calculated. </span>

<span>V1M1 × 1 = 25.62×0.0001288×1 = 0.003299856 </span>

<span>Now mass divided by molar mass = V1M1, so molar mass = mass/V1M1. </span>

<span>1.2587/0.003299856 = 381.44 g/mol</span>

4 0
3 years ago
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