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vlabodo [156]
3 years ago
5

A student titrated a 1.0115 g sample of potassium hydrogen phthalate (hkc8h4o4 204.2285g/mol with sodium hydroxide. the initial

buret reading was 1.16 ml and final reading 40.62 ml write a balanced equation
Chemistry
1 answer:
melomori [17]3 years ago
4 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
first determine the equation. KHP is a monoprotic acid, so it reacts with NaOH in a 1:1 ratio. 

<span>a) HKC8H4O4 + NaOH → NaKC8H4O4 + H2O </span>

<span>This allows you to calculate the molarity of NaOH, from the equation V1M1n2 = V2M2n1 </span>

<span>Molarity times volume will give you the number of moles of acid. You can work this out by dividing the mass used by the molar mass. For this question, you will have 1.0115/204.2285 moles KHP, so this value can be substituted for V1M1 in the equation. You need 38.46 mL of NaOH to titrate all the acid, so this will be V2. Now you find M2. </span>

<span>b) 1.0115/204.2285 × 1 = 38.46 × M2 × 1, so M2 = 0.0001288M </span>

<span>Now go on to part 3. Here, you use a similar calculation. The acid and base react in a 1:1 ratio, so n1 = n2 = 1. M2 = 0.1905 and V2 = 25.62. V1M1 will be calculated. </span>

<span>V1M1 × 1 = 25.62×0.0001288×1 = 0.003299856 </span>

<span>Now mass divided by molar mass = V1M1, so molar mass = mass/V1M1. </span>

<span>1.2587/0.003299856 = 381.44 g/mol</span>

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hope this helps:))

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