Firstly let's find hypotenuse(let it will be "n" of smaller triangle
Let use Pythagorean theorem

Now we need to find hypotenuse(x) of bigger triangle

The value of x must be rounded to 1 DP, so

Answer: x=24.1
V(t) = 2t^2 - 3t - 3
for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3
at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2
Answer:
-1
Step-by-step explanation:
For a line joining two points (x1, y1) and (x2, y2), it's slope is given as:

Here, the two points are (-1, 6) and (2, 3) in place of (x1, y1) and (x2, y2).
Solving for slope:




Hence, the slope of the line joining the given points is <u>-1.</u>
42 - 6 = 36 - 1
36 - 6 = 30 - 2
30 - 6 = 24 - 3
24 - 6 = 18 - 4
18 - 6 = 12 - 5
12 - 6 = 6 - 6
6 - 6 = 0 - 7
42/6 = 7
Answer:
v=2-2root7, v=2+2root7
Step-by-step explanation:
-2v+8(1+2v)=-90
-2-4v^2+8+16v=-90
6-4v^2+16v=-90
-4v^2+16v=-96
v=2-2root7, v=2+2root7