Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
You would have to add x1 + x2 and divide by 2. do the same with y1 and y2.
(1/2,-1/2)
The answer is A. it has two complex solutions
Answer:
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Step-by-step explanation:
Answer:
16 feet
Step-by-step explanation:
The length of the ladder=20 feet
Distance from the base of the ladder to the house = 12 feet
You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.
To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.
From Pythagoras theorem

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.