Which is the correct solution to the expression 3 + 5^2?

borishaifa [10]

Answer:

The total area of the figure is 52 in²

Step-by-step explanation:

This figure requires you to find the area of the square and the triangle separately, and then subtract the area of the triangle from the area of the square.

Find the area of the square

l=8in

A=l²

A=8²

A=64 in²

The area of the square is 64 in²

Find the area of the triangle

b=8in

h=3in

A=(bh)/2

A=(8*3)/2

A=24/2

A=12 in²

The area of the triangle is 64 in²

Now we need to subtract the areas

64-12=52 in²

The total area of the figure is 52 in²

8 0

4 years ago

Which 37/99 as a decimal <br> A) 0.037<br> B) 0.37<br> C) 0.37<br> D) 3.73

ladessa [460]

Answer:

b

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

KK Company sold 10,000 Super-Spreaders on December 31, 2019, at a total price of $1,000,000, with a warranty guarantee that the

TiliK225 [7]

The amounts to report at December 31, 2019 are:

Sales revenue $1,000,000

Warranty expense $40,000

Unearned warranty revenue $12,000

Warranty liability $40,000

Cash $1,012,000

<h3>Amount to reported on income and balance sheet:</h3>

Amount reported in Income

Sales revenue $1,000,000

Warranty expenses $40,000

Amount reported on the balance sheet:

Unearned service revenue $12,000

Cash $1,012,000

($1,000,000 + $12,000)

Warranty liability $40,000

Inconclusion the amounts to report at December 31, 2019 are: Sales revenue $1,000,000, Warranty expense $40,000, Unearned warranty revenue $12,000, Warranty liability $40,000 and Cash $1,012,000.

Learn more about amount to report on income and balance sheet here:brainly.com/question/26103668

5 0

3 years ago

you are shopping for disposable cameras to hand out at a party. the daytime cameras costs 2.75 dollars and the flash camera cost

LenKa [72]

The solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)

<h3>Write and solve a compound inequality for this solution. </h3>

The given parameters are:

Daytime cameras = $2.75
Flash camera = $4.25
Number of cameras = 20 cameras
Amount spent = Between $65 and $75

Represent the daytime camera with x and the flash camera with y.

So, we have:

x + y = 20

65 <=2.75x + 4.25y <= 75

Make y the subject in x + y = 20

y = 20 - x

Substitute y = 20 - x in 65 <=2.75x + 4.25y <= 75

65 <=2.75x + 4.25(20 - x) <= 75

Expand

65 <=2.75x + 85 - 4.25x <= 75

This gives

65 <=-1.5x+ 85 <= 75

Subtract 85 from the inequality

-20 <=-1.5x <= -10

Split the inequality

-1.5x >= -20 and -1.5x <= -10

Divide by -1.5

x <= 13.33 and x >= 6.67

Combine the inequality

6.67 <= x <= 13.33

<h3>List all of the solutions that involve whole numbers of cameras.</h3>

In (a), we have:

6.67 <= x <= 13.33

This means that:

x = 7, 8, 9, 10, 11, 12, 13

Recall that:

y = 20 - x

So, we have:

y = 13, 12, 11, 10, 9, 8, 7

So, the solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)