X=27 and y=11
if you let each number equal x and y we know the sum is 38 so x+y=38
and the smaller is 16 less than the larger
. so if we say the smaller number is 7 then x-16=y
these can be solved as a simultaneous equation. x+(x-16)=38
2x-16=38
2x=54
x=27
(27)-16=y
y=11
so the answer is x=27 y=11
Part 1We are given

. This can be rewritten as

.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula

The values of x are
Part 2Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a
quadratic function. Part 3.The first equation is

.
The second equation is

.
We have

Factoring, we have

Equating both factors to zero.

When the value of x is 6, the value of y is

When the value of x is -3, the value of y is

Therefore, the solutions are (6,38) or (-3,11)
Answer:
5.83095 or √34
Step-by-step explanation:
Find the difference between coordinates:
(x2-x1) = (-1 - -4) = 3
(y2-y1) = (-10 - -5) = -5
Square the results and sum them up:
(3)2 + (-5)2 = 9 + 25 = 34
Now Find the square root and that's your result:
Exact solution: √34 = √34
Approximate solution: 5.831
It should be about 22.55.