Answer:

Step-by-step explanation:
When
, we have
.
Combining like terms on the right side, we have
.
Finally, dividing by
we get
.
We note that
and
, so
.
So,
and we're done!
7! = 7*6*5*4*3*2*1 = 5040
None of the above
<u>Given</u>:
Given that JKL is a right triangle.
The measure of ∠L is 90°
The length of JL = 24, LK = 7, and KJ = 25.
We need to determine the value of sine of ∠K.
<u>Value of sin ∠K:</u>
The value of sin ∠K can be determine using the trigonometric ratio.
Thus, we have;

Substituting
, the side opposite to angle K is JL and the hypotenuse is JK
Thus, we have;

Substituting JL = 24 and JK = 25, we get;

Simplifying, we get;



Thus, the measure of sine of ∠K is 73.74°
<span>[4b-4]+3-b^2]+2b^3 ;b=2
= </span><span>[4(2)-4]+3-2^2]+2(2^3)
=</span> [8-4] + 3 - 4]+2(8)
= [4 + 3 - 4]+2(8)
=3 + 16
=19
answer is <span>A. 19</span>