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2 years ago

What is the angle relationship between ZBAC and ZDCA? F R G

Mathematics

1 answer:

horsena [70]2 years ago

4 0

The angle BAC and DCA are alternate interior angles , Option D is the right answer.

What are Parallel Lines ?

The lines in a plane which never intersect and are at a same distance always are called Parallel Lines.

In the given question it is given that there are two lines FG and DE

The lines are parallel to each other , and transversal are AC and BC .

The angle BAC and DCA are alternate interior angles as AC is the transversal of the parallel lines.

Option D is the right answer.

To know more about Parallel Lines

brainly.com/question/16701300

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(x-2)(-5x^2+x)=(x)(-5x^2)+(x)(x)+(-2)(-5x^2)+(-2)(x) is an exsample of

e-lub [12.9K]

this is an example of linear equations is one variable

6 0

3 years ago

. Aladdin found a cave filled with boxes of gold, measuring 2 inches × 2 inches × 2 inches, and boxes of silver, measuring 1 inc

Viktor [21]

Answer:

Step-by-step explanation:

volume of box=6×6×7 in³

he fits gold 2×2×2

so he fits it in 6×6×6

so number of gold boxes=(6×6×6)/(2×2×2)=27

remaining space=1×6×6

number of silver boxes=(1×6×6)/(1×1×1)=36

total boxes he took=27+36=63

4 0

3 years ago

Square of a standard normal: Warmup 1.0 point possible (graded, results hidden) What is the mean ????[????2] and variance ??????

LenaWriter [7]

Answer:

$E[X^2]= \frac{2!}{2^1 1!}= 1$

$Var(X^2)= 3-(1)^2 =2$

Step-by-step explanation:

For this case we can use the moment generating function for the normal model given by:

$\phi(t) = E[e^{tX}]$

And this function is very useful when the distribution analyzed have exponentials and we can write the generating moment function can be write like this:

$\phi(t) = C \int_{R} e^{tx} e^{-\frac{x^2}{2}} dx = C \int_R e^{-\frac{x^2}{2} +tx} dx = e^{\frac{t^2}{2}} C \int_R e^{-\frac{(x-t)^2}{2}}dx$

And we have that the moment generating function can be write like this:

$\phi(t) = e^{\frac{t^2}{2}$

And we can write this as an infinite series like this:

$\phi(t)= 1 +(\frac{t^2}{2})+\frac{1}{2} (\frac{t^2}{2})^2 +....+\frac{1}{k!}(\frac{t^2}{2})^k+ ...$

And since this series converges absolutely for all the possible values of tX as converges the series e^2, we can use this to write this expression:

$E[e^{tX}]= E[1+ tX +\frac{1}{2} (tX)^2 +....+\frac{1}{n!}(tX)^n +....]$

$E[e^{tX}]= 1+ E[X]t +\frac{1}{2}E[X^2]t^2 +....+\frac{1}{n1}E[X^n] t^n+...$

and we can use the property that the convergent power series can be equal only if they are equal term by term and then we have:

$\frac{1}{(2k)!} E[X^{2k}] t^{2k}=\frac{1}{k!} (\frac{t^2}{2})^k =\frac{1}{2^k k!} t^{2k}$

And then we have this:

$E[X^{2k}]=\frac{(2k)!}{2^k k!}, k=0,1,2,...$

And then we can find the $E[X^2]$

$E[X^2]= \frac{2!}{2^1 1!}= 1$

And we can find the variance like this :

$Var(X^2) = E[X^4]-[E(X^2)]^2$

And first we find:

$E[X^4]= \frac{4!}{2^2 2!}= 3$

And then the variance is given by:

$Var(X^2)= 3-(1)^2 =2$

7 0

3 years ago

The temperature at 6:00 am was -12 Fahrenheit. The temperature increased by 1/2 Fahrenheit each hour for 6 hours. What was the t

zlopas [31]

Answer: -9°F

Step-by-step explanation:

From the question, we are told that the temperature at 6:00 am was -12 Fahrenheit and that the temperature increased by 1/2 Fahrenheit each hour for 6 hours.

The temperature, in degrees Fahrenheit, at noon would be:

= -12°F + 1/2(6)

= -12°F + 3°F

= -9°F

6 0

3 years ago

A tower made of wooden blocks measures 114 feet high. Then a block is added that increases the height of the tower by 8 inches.

satela [25.4K]

Answer:

4. 23 in

Step-by-step explanation:

The tower is 1 1/4 feet high, then 8 inches are added. Well, we can't just add those two numbers. We have to change the units! Change everything to inches.

1 1/4 feet is equal to 12 inches + 3 inches = 15 inches, because a foot = 12 inches.

Add 8 inches to 15, and you get 23 inches.

<u>The answer is 4. 23 in. </u>

4 0

4 years ago