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love history [14]
3 years ago
5

at a concession stand 9 slices of pizza and 5 soft pretzels cost $33.25. If 4 slices of pizza and 6 soft pretzels cost $19.50. W

hat is the cost of a soft pretzel?
Mathematics
2 answers:
jok3333 [9.3K]3 years ago
6 0

Answer:

The cost of soft pretzel is $1.25

Step-by-step explanation:

Let $x be the price of one slice of pizza and $y be the price of one soft pretzel.

1. 9 slices of pizza cost $9x and 5 soft pretzels cost $5y. Together they cost $33.25, then

9x+5y=33.25.

2. 4 slices of pizza cost $4x and 6 soft pretzels cost $6y. Together they cost $19.50, then

4x+6y=19.50.

3. Solve the system of two equations:

\left\{\begin{array}{l}9x+5y=33.25\\4x+6y=19.50\end{array}\right..

Multiplythe first equation by 4, the second equation by 9 and subtract them:

4(9x+5y)-9(4x+6y)=4\cdot 33.25-9\cdot 19.50,\\ \\36x+20y-35x-54y=133-175.5,\\ \\-34y=-42.5,\\ \\y=\$1.25.

Then

4x+6\cdot 1.25=19.50,\\ \\4x=19.50-7.50,\\ \\4x=12,\\ \\x=\$3.

max2010maxim [7]3 years ago
4 0

Answer: Each soft pretzel cost $1.25

Step-by-step explanation:

Hi, we have to write an equation for each case:

9 x + 5 y = 33.25

4x +6 y = 19.50

Where x is the price of 1 slice of pizza, and y is the price of each soft pretzel.

Multiplying the first equation by 4, and the second equation by 9

36x +20y =133

36x +54y =175.5

And subtracting the first equation to the second equation

36x +54y =175.5

-

36x +20y =133

____________

34 y = 42.5

Solving for y  

y =42.5/34

y = $1.25

Each soft pretzel cost $1.25

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a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
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Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

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We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

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A_y=50sin(89.75) so

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Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

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