Ay^2+2ay-3a
a(y^2+2y-3)
a(y-1)(y+3)
<h3>
Answer: Angle Q = 133 degrees</h3>
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Work Shown:
Recall that for any triangle, the three angles always add to 180
P+Q+R = 180
(x+13) + (10x+13) + (2x-2) = 180
(x+10x+2x) + (13+13-2) = 180
13x+24 = 180
13x = 180-24
13x = 156
x = 156/13
x = 12
Now that we know x, we can find the angle measures
- angle P = x+13 = 12+13 = 25 degrees
- angle Q = 10x+13 = 10*12+13 = 120+13 = 133 degrees
- angle R = 2x-2 = 2*12-2 = 24-2 = 22 degrees
As a way to check if we have the right answer or not, we see that,
P+Q+R = 25+133+22 = 180
So the answer is confirmed.
Answer: Approximately d = 208.72
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Work Shown:
Make sure your calculator is in radian mode
A quick way to check is to compute cos(pi) and you should get -1
cos(angle) = adjacent/hypotenuse
cos(x) = 200/d
cos(0.29) = 200/d
d*cos(0.29) = 200
d = 200/cos(0.29)
d = 208.715135166392 which is approximate
d = 208.72
I rounded to two decimal places since x is rounded in that manner as well. Round however else you need if your teacher instructs.
My final answer is automatic 588
