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vodka [1.7K]
2 years ago
11

Does anyone know the answer

Chemistry
1 answer:
dexar [7]2 years ago
3 0

Answer:

Depends, see below.

Explanation:

This requires some judgement.  I would say "neither accurate nor precise."  The individual data points are relatively scattered, so it is not precise,  Assuming the "o" means the correct value,   there is, again, some disturbing variance, although this conclusion depends on the scale of the data axes, which isn't shown.  If the sale were in miles and we were planning a missle strike, you would not consider the hits very accurate.  If the sale were in cm foir the same mission, I'd vote accurate.

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Answer:

9.53*10^{17} atoms of 40K

Explanation:

You can use the molecular mass and the Avogadro´s number, in the following formula:

N_{40K=\frac{m_{KCl}}{M_{MKCl}}}*N_{Avogadro}*(IA_{40k})

where m_{KCl} is the sample mass, M_{KCl} is the molecular mass of the KCl and IA(40K) is the isotopic abundance of 40K.

Now replacing the values, you can find:

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