Question 22 Write the empirical formula for at least four ionic compounds that could be formed from the following ions:

Chemistry

1 answer:

Ivenika [448]3 years ago

7 0

Answer:

We can use the criss-cross method to work out the formulas.

Explanation:

The steps are

Write the symbols of the anion and cation.
Criss-cross the numbers of the charges to become the subscripts of the other ion.
Write the formula with the new subscripts.
Divide the subscripts by their highest common factor.
Omit all subscripts that are 1.

When we use this method, the formula for the compound formed from NH₄⁺ and PO₄³⁻ becomes (NH₄)₃PO₄.

The table below lists the formulas for the possible combinations.

$\begin{array}{ccc}& \textbf{PO}_{4}^{3-} & \textbf{ClO}_{3}^{-}\\\textbf{NH}_{4}^{+} & \text{(NH$_{4}$)$_{3}$PO$_{4}$} & \text{NH$_{4}$ClO}_{3}\\\textbf{Fe}^{3+} & \text{FePO}_{4} & \text{Fe(ClO$_{3}$)}_{3}\\\end{array}$

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three moles of sodium carbonate are mixed with two moles of lead nitrate in aqueous solution, leading to formation of a solid pr

aleksandrvk [35]

There are 4 moles of spectator ions that remain in solution.

The equation of the reaction is;

Na2CO3(aq) + Pb(NO3)2(aq) -------> PbCO3(s) + 2NaNO3(aq)

We have to determine the limiting reactant. This is the reactant that yields the least amount of product. Note that the spectator ions are Na^+ and NO3^- that form NaNO3.

For Na2CO3

1 mole of Na2CO3 yields 2 moles of NaNO3

3 moles of Na2CO3 yields 3 × 2/1 = 6 moles of NaNO3

For Pb(NO3)2

1 mole of Pb(NO3)2 yields 2 moles of NaNO3

2 moles of Pb(NO3)2 yields 2 × 2/1 = 4 moles of NaNO3

We can see that Pb(NO3)2 is the limiting reactant.

Since [NaNO3] = [Na^+] = [NO3^-], it follows that there are 4 moles of spectator ions that remain in solution.

Learn more: brainly.com/question/22885959

6 0

2 years ago

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