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Lostsunrise [7]
3 years ago
8

How many ne atoms are contained in 32.0g of the element?

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
7 0
(32.0 g Ne) / (20.1797 g Ne/mol) × (6.022 × 10^23 atoms/mol) = 9.55 × 10^23 atoms N3
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1-A

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Pure R,R-hydrobenzoin (side product of meso-hydrobenzoin) has a melting point of 148°C. a) What do you expect the melting point
Alexandra [31]

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3 0
3 years ago
g In the absence of allosteric effectors, the enzyme phosphofructokinase displays Michaelis–Menten kinetics (see Fig. 7.15). The
Furkat [3]

Answer:

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Explanation:

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v_o=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}

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Where:

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[S] = Concatenation of substrate

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On substituting all the given values

We have :

\frac{v_o}{V_{max}}=0.90

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K_m=0.0111 mM

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6 0
3 years ago
An unknown compound in the lab is either LiOH, CaF2, or LiF. If the sample has a mass of 260 grams and contains 3.33 moles, what
sergij07 [2.7K]

Answer:

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Explanation:

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the others multiplied were nowhere near 260 grams either

3 0
3 years ago
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