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fgiga [73]
2 years ago
8

6. The gas in a steel cylinder is at 55 °C and a pressure of 965 mmHg. What would be the temperature,

Chemistry
1 answer:
ohaa [14]2 years ago
6 0

Answer:

91.4°C

Explanation:

Gay - Lussac Law => T ∝ P => T = kP => k = T/P with volume (V) and mass (n) constant.

For two different Temperature (T)-Pressure (P) conditions

k₁ = k₂ => T₁/P₁ = T₂/P₂ => T₂ = T₁(P₂/P₁)

T₁ = 55°C = (55 + 273)K = 328K      

P₁ = 965 mmHg

T₂ =  ?

P₂ = 850 mmHg

T₂ = T₁(P₂/P₁) = 328K(850 mmHg/965 mmHg) = 364K = (364 - 273)°C = 91.4°C

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Need help !!!!! ASAP
Julli [10]
<h2>Hello!</h2>

The answer is:

The new volume will be 1 L.

V_{2}=1L

<h2>Why?</h2>

To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.

To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.

Boyle's Law equation is:

P_{1}V_{1}=P_{2}V_{2}

So, we are given the information:

V_{1}=2L\\P_{1}=50kPa\\P_{2}=100kPa

Then, isolating the new volume and substituting into the equation, we have:

P_{1}V_{1}=P_{2}V_{2}

V_{2}=\frac{P_{1}V_{1}}{P_{2}}

V_{2}=\frac{50kPa*2L}{100kPa}=1L

Hence, the new volume will be 1 L.

V_{2}=1L

Have a nice day!

4 0
3 years ago
What type of organic reaction produces both water and carbon dioxide
nalin [4]
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</span>
6 0
3 years ago
How many neutrons does element X have if its atomic number is 31 and its mass number is 80?
MrRissso [65]

49 neutrons in each nucleus.

<h3>Explanation</h3>

For each nucleus:

Mass number = Number of protons + Number of neutrons.

The atomic number of a nucleus is the same as its number of protons. The atomic number of the nucleus here is 31. There are 31 protons in each nucleus.

  • Mass number = 80;
  • Number of protons = Atomic number = 31;
  • The number of neutrons is to be found.

Again,

Mass number = Number of protons + Number of neutrons.

80 = 31 + Number of neutrons.

Number of neutrons = 80 - 31 = 49.

5 0
3 years ago
An isotope with a mass number of 193 has 116 neutrons. What is the atomic number of this
Zinaida [17]

Answer:

Atomic number of this  isotope = 77

Explanation:

Given that,

Mass number = 193

No of neutrons = 116

We need to find the atomic no of this isotope.

We know that,

Atomic mass = No of protons + No. of neutrons

Also, atomic no = no of protons

So,

Atomic mass = atomic no + No. of neutrons

⇒ Atomic no = Atomic mass - no of neutrons

Atomic no = 193 - 116

Atomic no = 77

Hence, 77 is the atomic no of the isotope.

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