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2 years ago

6. The gas in a steel cylinder is at 55 °C and a pressure of 965 mmHg. What would be the temperature,

Chemistry

1 answer:

ohaa [14]2 years ago

6 0

Answer:

91.4°C

Explanation:

Gay - Lussac Law => T ∝ P => T = kP => k = T/P with volume (V) and mass (n) constant.

For two different Temperature (T)-Pressure (P) conditions

k₁ = k₂ => T₁/P₁ = T₂/P₂ => T₂ = T₁(P₂/P₁)

T₁ = 55°C = (55 + 273)K = 328K

P₁ = 965 mmHg

T₂ = ?

P₂ = 850 mmHg

T₂ = T₁(P₂/P₁) = 328K(850 mmHg/965 mmHg) = 364K = (364 - 273)°C = 91.4°C

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