1 = sin²0 + cos²0
sin²0 = 1 - cos²0
sin²0 = 1 - 11/36
sin²0 = 25/36
sin 0 = 5/6 or -5/6
In the first quadrant, the values for sin, cos and tan are positive.
sin0 = 5/6
When a tangent line (13.5 cm) and a secant (lines x + 8.45 cm) intersect then:
tangent line^2 = 8.45 * (8.45 + x)
13.5^2 = 71.4025 + 8.45 x
182.25 -71.4025 = 8.45x
8.45 x = 110.8475
x = 13.1180473373
x = 13.1 (rounded)
Source:
1728.com/circangl.htm
Left side = 170-58 =121'
Bottom side = 96-4 =92'
Now let's calculate the upper oblique (slantwise) side by Pythagoras
oblique² = 92²+28² = 9248 & oblique =√9248 = 96.167'
The perimeter of the backyards = 96.167+93+92+121 = 402.167 ft
Answer:
It would last for 3.2 days.
Step-by-step explanation:
100 men = 8 days
10 men = 0.8 days
60 men = 0.8 x 6 = 4.8 days
Now you subtract the days of 100 men and 60 men
8 - 4.8 = 3.2 days
Hope this helps!
