Answer:
???
Step-by-step explanation:
Answer:
30 dollars a week
Step-by-step explanation:
2100/70 is 30
Seven more than 3 times a number is equal to 49 can be put into an equation form, which would be 7 + 3x = 49. With this equation we can work it out, first we will subtract 7 from both sides of the equation to cancel out the 7. 49 - 7 = 42. Now we have 3x = 42. To isolate x and give us the answer we will divide by 3 on both sides, since 3 is being multiplied by x. This will give us our answer, which is 14.
Answer:
0.5969 = 59.69% probability that it was a flight of airline A
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Left on time.
Event B: From airline A.
Probability of a flight leaving on time:
81% of 48%(airline A).
61% of 26%(airline B)
40% of 26%(airline C). So
![P(A) = 0.81*0.48 + 0.61*0.26 + 0.40*0.26 = 0.6514](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.81%2A0.48%20%2B%200.61%2A0.26%20%2B%200.40%2A0.26%20%3D%200.6514)
Probability of leaving on time and being from airline A:
81% of 48%. So
![P(A \cap B) = 0.81*0.48 = 0.3888](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%200.81%2A0.48%20%3D%200.3888)
What is the probability that it was a flight of airline A?
![P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3888}{0.6514} = 0.5969](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D%20%3D%20%5Cfrac%7B0.3888%7D%7B0.6514%7D%20%3D%200.5969)
0.5969 = 59.69% probability that it was a flight of airline A