If the angle measures of a triangle can be expressed as 4x + 6, 7x-14, and 48-x, what is the value of the smallest angle measure

a tub shaped like a cylinder with a diameter of 18 inches, And a height of 20 inches Is filled to the top with water. Six spheri

jasenka [17]

The approximate amount of water that remains in the tub after the 6 spherical balls are placed in the tub are 3479.12 in³.

<h3>What is the approximate amount of water that remains in the tub?</h3>

The first step is to determine the volume of the cylinder.

Volume of the tub = πr²h

Where:

r = radius = diameter / 2 = 18/2 = 9 inches
h = height
π = 3.14

3.14 x 9² x 20 = 5086.8 in³

The second step is to determine the volume of the 6 balls.

Volume of a sphere= 4/3πr³

r = diameter / 2 = 8/2 = 4 inches

6 x (3.14 x 4/3 x 4³) = 1607.68 in³

Volume that remains in the tub = 5086.8 in³ - 1607.68 in³ = 3479.12 in³

To learn more about the volume of a sphere, please check: brainly.com/question/13705125

#SPJ1

4 0

2 years ago

Find the area of each shape

a_sh-v [17]

The square is 130 in squared and the other shape is 54 in squared. If you're looking for the sum of the whole thing, its 185 in squared.
square: 13*10=130
triangle: 7*4= 28/2=14
rectangle: 10*4=40

5 0

3 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago

Find the distance between (8,8) and (3,1)

Vesnalui [34]

Answer:

About 8.6

Step-by-step explanation:

d=(x2-x1)^2+(y2-y1)^2

8=x1 8=y1 3=x2 1=y2

(3-8)^2+(1-8)^2

(-5)^2+(-7)^2

25+49

74

take the square root and you get about 8.6

3 0

3 years ago

The students in Suzanne's school are painting a rectangular mural outside the building that will be 15 feet by 45 feet. Scale dr

Katarina [22]

Answer:

The dimensions on paper are 1.992ft by 5.976ft with a scale factor of 7.53

Step-by-step explanation:

The first step will be to find the diagonal of the rea life mural.

We can use Pythagoras' Theorem to do this.

Diagonal = $\sqrt{15^2 +45^2 }$ =47.43 feet.

Now we have the real-life diagonal, we will now relate the diagonal of the painting outside with the one on paper. We can do this by dividing the two diagonals.

This will be 47.43 / 6.3 units = 7.53.

The scale factor is 7.53

To get the dimensions of the length and the breadth on paper, we divide the outside dimensions by the scale factor.

This will be

Length = 15/ 7.53 = 1.992

Breadth = 45/7.53 = 5.976

Therefore, the dimensions on paper are 1.992ft by 5.976ft with a scale factor of 7.53

3 0

2 years ago