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sergij07 [2.7K]
2 years ago
6

Three numbers are in the ratio 2:5:7 and their lcm is 490 find the square root of the largest number

Mathematics
1 answer:
ohaa [14]2 years ago
5 0

Answer:

49

Step-by-step explanation:

The ratio of three numbers = 2:5:7

Then the numbers are 2x,5x and 7x

Given that the LCM of these numbers  = 490

LCM of 2x,5x,7x is 2×5×7×x = 70x

Then, we have 70x = 490

x  = 7

Hence, the numbers are 14, 35 and 49

Largest number = 49

∴The square root of the largest number = 7

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<u>Answer: </u>

The complete factorization of 4 x^{2}-24 x y+36 y^{2} are 4(x-3y)(x+3y)

<u>Solution:</u>

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4 x^{2}-24 x y+36 y^{2}

Take common value in all the three term.so we take 4 as common term in the above expression

4 x^{2}-24 x y+36 y^{2}=4\left(x^{2}-6 x y+9 y^{2}\right)

Now factorize the expression \left(x^{2}-6 x y+9 y^{2}\right)

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-3,-3 are the numbers which satisfy the above condition.

When we add -3-3=Sum is 6

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So the expression will become as x^{2}-6 x y+9 y^{2} = x^{2}-3 x y-3 x y+9 y^{2}

Take the common term

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