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Verdich [7]
2 years ago
8

Rhombus JKLM is dilated with center (-4, 7) and scale factor to produce rhombus J'K'L'M'. Fill in the table below to determine t

he missing coordinates.

Mathematics
1 answer:
bija089 [108]2 years ago
3 0

Transforming the rhombus JKLM by dilation with a scale factor of 1/4 and center at D(0, 3), gives;

  • J'(0, 2.5)

  • L(-16, 19)

<h3>What formula can be used to find the coordinates of the image following a dilation?</h3>

From the question, we have;

Center of dilation = D(0, 3)

Scale factor of dilation = 1/4

The given points are;

  • J(0, 1), L'(-4, 7)

The required points are J' and L

Given that the x-coordinate of <em>J </em>is the same as the center of dilation, we have;

The x-coordinate of <em>J' </em>= 0

The formula for finding the coordinates following a dilation is presented as follows;

Dilation;

(x, y) → (k(x - a) + a, k(y - b) + b)

Where;

Center of dilation = (a, b)

Scale factor = k

Therefore;

J(0, 1)

J'(0.25•(0 - 0) + 0, 0.25•(1 - 3) + 3)

The coordinates of <em>J' </em>is therefore;

  • J'(0, 2.5)

L'(-4, 7) = L(0.25(x - 0) + 0, 0.25(y - 3) + 3)

0.25(x - 0) + 0 = -4

Therefore;

x = -16

0.25•(y - 3) + 3 = 7

y - 3 = (7 - 3)/0.25 = 16

y = 19

  • The coordinates of <em>L </em>is<em> </em>therefore (-16, 19)

Learn more about dilation transformation here:

brainly.com/question/14263066

#SPJ1

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