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Maksim231197 [3]
3 years ago
10

If xy = a and x2 + y2 = b, which of the following is equivalent to 9b – 18a ?

Mathematics
1 answer:
Llana [10]3 years ago
5 0

Answer:

  A)  (3x -3y)²

Step-by-step explanation:

9b -18a = 9(x² +y²) -18xy

  = 9x² -18xy +9y²

  = (3x -3y)² . . . . . matches choice A

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yawa3891 [41]

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

7 0
2 years ago
In the figure below, segment AC is congruent to segment AB:
stepladder [879]

Answer: A. "Segment AD bisects angle CAB." is the right answer.

Step-by-step explanation:

Given : In ΔABC ,AC≅AB.

⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )

Now in ΔACD and ΔABD

AD=AD (common)....(2)

Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.

If AD bisects ∠CAB then ∠CAD=∠BAD..(3)

Now again Now in ΔACD and ΔABD

∠ACB=∠CBA [from (1)]

AD=AD [common]

∠CAD=∠BAD [from (3)]

So by ASA congruency criteria ΔADC≅ΔABD.

7 0
3 years ago
Which of these are expressions?
Ugo [173]

Answer:

1x0

2 x 11

1x0

Hope this helps! :) Please rate brainliest

7 0
3 years ago
15 children voted for their favorite color. The votes for red and blue together we're double the votes for green and yellow toge
Artist 52 [7]
10 for red and blue together and 5 for green and yellow together
3 0
3 years ago
Read 2 more answers
What is the answer to 5x5
poizon [28]

Answer:

25

Step-by-step explanation:

5x5

5+5+5+5+5

10+10+5

20+5

25

7 0
3 years ago
Read 2 more answers
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