Question

a cone is created by rotating an isosceles right triangle with leg length 2 about one of its legs. its surface area is $\pi$ times what number?

Answer 1

The surface area is $4\sqrt{2} \pi$ units.

This problem is related to the triangle and solid figures.

If we rotate a triangle along one of its legs then it will form a cone and the radius of the cone will be the length of the base of the triangle and the hypotenuse of the triangle will be the slant height of the cone.

The length of the the triangle legs is given to be 2 units.

Length of the hypotenuse=$\sqrt{2^{2} +2^{2} }$

                                        = $2\sqrt{2}$ units.

Now the area of the cone is given by $\pi rl$ where r is the radius of the cone and l is the slant height of the cone.

Surface area of cone = $\pi *2*2\sqrt{2}$

                                  = $4\sqrt{2} \pi$ units

So, the surface area of cone is $4\sqrt{2} \pi$ units.

To learn more about triangles visit the link:

brainly.com/question/2773823

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