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Lera25 [3.4K]
1 year ago
14

If y=kx and k is constant, what's the proportional relationship between x and y?

Mathematics
1 answer:
Anon25 [30]1 year ago
5 0

Answer: k

Step-by-step explanation:

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Please Can Someone Tell Me The Area??
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Answer:

66 I am pretty sure

Step-by-step explanation:

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60 + 6 = 66

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It is possible none of the choices is the solution?
velikii [3]

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Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
Determine the common ratio and find the next three terms of the geometric sequence t8, t5, t2
attashe74 [19]
The common ratio of the given geometric sequence is the number that is multiplied to the first term in order to get the second term. Consequently, this is also the number multiplied to the second term to get the third term. This cycle goes on and on until a certain term is acquired. In this item, the common ratio r is,

    r = t⁵/t⁸ = t²/t⁵

The answer, r = t⁻³.

The next three terms are,

    n₄ = (t²)(t⁻³) = t⁻¹
    n₅ = (t⁻¹)(t⁻³) = t⁻⁴
    n₆ = (t⁻⁴)(t⁻³) = t⁻⁷

The answers for the next three terms are as reflected above as n₄, n₅, and n₆, respectively. 
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3 years ago
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