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2 years ago

Please Help with this Question that I gave you

Mathematics

1 answer:

Nikitich [7]2 years ago

4 0

Answer:

536

Step-by-step explanation:

To find how many red gumballs where put into the machine: 253-98 = 155

To find how many blue gumballs where put into the machine: 155- 27 = 128

To then find the total amont of gumballs placed into the machine:

253+155+128 = 536 gumballs where placed into the machine in total

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Alex17521 [72]

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3 years ago

Por un tubo de 2.5 cm de diámetro fluye agua con una repidez de 20 cm/s ¿Cuál es el valor del flujo y el gasto del agua?

kompoz [17]

Answer:

El flujo y gasto de agua es aproximadamente 98.175 centímetros cúbicos por segundo.

Step-by-step explanation:

El gasto del agua ( $Q$ ), medido en centímetros cúbicos por segundo, es el flujo que pasa a través del tubo. La ecuación para determinar el gasto es:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot v$ (1)

Donde:

$D$ - Diámetro del tubo, medido en centímetros.

$v$ - Velocidad del flujo, medida en centímetros por segundo.

Si sabemos que $D = 2.5\,cm$ y $v = 20\,\frac{cm}{s}$ , entonces el flujo y gasto del agua es:

$Q = \frac{\pi}{4}\cdot (2.5\,cm)^{2}\cdot \left(20\,\frac{cm}{s} \right)$

$Q \approx 98.175\,\frac{cm^{3}}{s}$

El flujo y gasto de agua es aproximadamente 98.175 centímetros cúbicos por segundo.

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3 years ago

Express the following as indicated. (1) 5 cm (in and km)

Fynjy0 [20]

Answer:

<u>Convert in to cm and km to cm:</u>

1 in = 2.54 cm ⇒ 1 cm = 1/2.54 in ⇒ 5 cm = 5/2.54 in ≈ 1.9685 in
1 km = 100000 cm ⇒ 1 cm = 0.00001 km ⇒ 5 cm = 0.00005 km

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3 years ago

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lbvjy [14]

The Given Quadratic Equation is bx + c = 0

$\sf \: so \: \: \: \: \: a = 9 \: \: \: \: \: \: \: \: \: \: b = 7 \: \: \: \: \: \: \: \: c = - 2$

We Know That Determinant (D) = b²– 4ac

$\sf \: (D) = {7}^{2} - 4 \times 9 \times - 2$

$\sf \: (D) = 49 - 36 \times - 2$

$\sf \: (D) = 49 + 72$

$\boxed{ \underline \color{skyblue}{\sf \: (D) = 121 > 0}}$

The Determinant of The Equation is Positive So,

The Expression Contains Real Root.

<h3>Hope Helps~</h3>

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