All categories

1 year ago

Which structural damage could be expected if a Category 3 hurricane is predicted to hit an area?(1 point)

1 answer:

8 0

The structural damage which could be expected if a Category 3 hurricane which is predicted to hit an area is high percentage of framed homes could be destroyed, with total roof failure and wall collapse and is denoted as option C.

<h3>What is Hurricane?</h3>

This refers to the rapidly rotating storm which has a low-pressure center and is characterized by strong winds ad thunderstorms and of different types such as category 1 to 3.

Category 3 hurricane leads to loss of lives and properties which is depicted as framed homes being destroyed with total roof failure and wall collapse which is why option C was chosen.

Read more about Hurricane here brainly.com/question/2835662

#SPJ1

You might be interested in

4. If you were an astronaut on the Moon, what would you experience? What would you see from your perspective?

hjlf

an astronaut on the Moon could experience zero gravity, and would see stars and Earth.

8 0

3 years ago

Read 2 more answers

7. Which phase changes require a gain of energy (heat)?

Keith_Richards [23]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

A closed pipe creates a

lina2011 [118]

Answer:

375 hz

Explanation:

Trust me

5 0

3 years ago

What concept or principle best explains why

andreev551 [17]

Answer:

d. Newton's first law

I hope this helps you

5 0

3 years ago

Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur

BARSIC [14]

Answer:

$v_A=7667m/s\\\\v_B=7487m/s$

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

$F_g=\frac{GMm}{R^{2} }$

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

$F_c=m\frac{v^{2}}{R}$

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

$\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}$

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So $R_A=6774km=6.774*10^6m$ and $R_B=7103km=7.103*10^6m$ (Since $R_{earth}=6371km$ ). Then, we get:

$v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s$

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

7 0

3 years ago