All categories

3 years ago

How quickly can the light struck reaction occur when unprotected beer is exposed to the proper wavelength of light?

Physics

1 answer:

OleMash [197]3 years ago

5 0

Answer:

If the beer is in the crystal clear glass, unprotected from the sunlight then it will starts skunking within 30 seconds. The reason behind the skunking of the beer is a photo chemical reaction. So one can avoid the skunking of beer by packaging it in the cans or opaque bottles.

Explanation:

You might be interested in

Identify the type of circuit in which the user retains the physical path through the network, but only for the duration of a cal

Naddika [18.5K]

Switched Circuit: This type of connection only maintains a dedicated physical circuit or path between two network nodes for the duration of the connection before data may be transmitted.

<h3>What do you mean by circuit?</h3>

A circuit in electronics is a complete circular channel via which electricity flows. A current source, conductors, and a load make up a straightforward circuit. The term circuit can be used in a broad sense to refer to any permanent path that energy, data or a signal can go through.

<h3>What are the 3 types of circuits?</h3>

Circuits can be divided into three categories: series, parallel, and series-parallel. The typical configuration of a single electrical circuit includes one or more resistance or load devices.

<h3>What function does a circuit represent?</h3>

The closed loop in which electricity can move is referred to as a circuit. Electricity can flow in a closed circuit without interruption from the power source through the conductor or wire to the load before returning to the ground or power source.

To know more about Circuit visit:

brainly.com/question/21505732

#SPJ4

5 0

2 years ago

A 1,800-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 3.00 m before coming into contact

Jobisdone [24]

Answer:

average force = 385,140 N

Explanation:

from the question we are given the following

mass (m) = 1800 kg

distance of fall (d) = 3 m

driven distance (l) = 14.4 cm = 0.144 m

acceleration due to gravity (g) = 9.8 m/s^{2}

work done = average force x driven distance.....equation 1

and

work done = change in kinetic energy + change in potential energy

work done = (0.5 x m x (v^{2} - u^{2})) + (m x g x (-d-l))

Initial velocity (u) and final velocity (v) are zero because the pile driver is it rest before it moves to hit the pile and after hitting the pile.
The changes in length for the potential energy are negative because the pile moves downward

we now have work done = (m x g x (-d-l))...equation 2

now equating the two equations for work done we have

average force x driven distance = (m x g x (-d-l))

average force x 0.144 = 1800 x 9.8 x (-3-0.144)

average force = (1800 x 9.8 x (-3-0.144)) ÷ 0.144

average force = 385,140 N

3 0

3 years ago

If no friction acts on a diver during a dive, then which of the following statements is true? A) The total mechanical energy of

EleoNora [17]

If no frictional work is considered, then the energy of the system (the driver at all positions is conserved.

Let
position 1 = initial height of the diver (h₁), together with the initial velocity (v₁).
position 2 = final height of the diver (h₂) and the final velocity (v₂).

The initial PE = mgh₁ and the initial KE = (1/2)mv₁²
where g = acceleration due to gravity,
m = mass of the diver.
Similarly, the final PE and KE are respectively mgh₂ and (1/2)mv₂².
PE in position 1 is converted into KE due to the loss in height from position 1 to position 2.

Therefore
(KE + PE) ₁ = (KE + PE)₂

Evaluate the given answers.
A) The total mechanical energy of the system increases.
FALSE

B) Potential energy can be converted into kinetic energy but not vice versa.
TRUE

C) (KE + PE)beginning = (KE + PE) end.
TRUE

D) All of the above.
FALSE

4 0

3 years ago

Read 2 more answers

There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.

Sloan [31]

Via half-life equation we have:

$A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }$

Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes. By plugging those values in we get:

$A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g$

There is 6.25 grams left of Ra-229 after 12 minutes.

4 0

4 years ago

When an excited electron in a hydrogen atom falls from the n = 3 to the n = 2 level, a photon of red light is emitted from the a

Kaylis [27]

Answer: 653.33 nm ; 1875, 24 nm

Explanation: For the first case we have to use the Balmer series for the hydrogen when the atom falls from the n = 3 to the n = 2. So for the second transtions for the hydrogen we use the Paschen serie. To do the calculation we need to know the Ryberg constant that is equal to 1.097 * 10^7 m^-1. In the attach is shown the expression for spectral series used for calculation.

3 0

3 years ago