Conduction is the transfer of ___________ ___________ from one molecule to another by direct contact

Standing still, Bruce, the quarterback, gets tackled by Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s. Upon collision, B

tatyana61 [14]

$\\ \sf\longmapsto \Delta P=P$

$\\ \sf\longmapsto m1v1=m2v2$

$\\ \sf\longmapsto 90(7)=m2(10)$

$\\ \sf\longmapsto 10m2=630$

$\\ \sf\longmapsto m2=\dfrac{630}{10}$

$\\ \sf\longmapsto m2=63kg$

Bruces mass is 63kg

3 0

2 years ago

Read 2 more answers

When laser light of wavelength 632.8 nm passes through a diffraction grating, the first bright spots occur at ± 17.8 ∘ from the

o-na [289]

The equation we use is mλ=dsinθ for intensity maximas. We are given at the first maximum (m=1), it occurs at 17.8 degrees. Thus we can solve for d by substituting known values into our equation.

(1) (632.8*10^-9m)=dsin(17.8) => d = 2.07*10^-6m

Next we want to find the angle at the second maximum (m=2) so we need to solve for θ.

(2) (632.8*10^-9m) = (2.07*10^-6m)sinθ

θ=37.69 degrees

Hopes this helps!

P.S. I hope this is right. If not sorry in advance.

3 0

3 years ago

Can someone help with my physics homework? please

Murrr4er [49]

Answer:

a) 19536 joules of work are done.

b) The work is done by the engine on the structure of the cart.

c) There are three options: (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.

d) 24442 joules of work are done.

e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.

f) The bigger engine uses more gas to go 22 meters.

g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.

Explanation:

a) If force applied in the cart is uniform, that is, constant in magnitude and direction and is parallel to distance travelled by the car, the work done on the cart is defined by the following equation:

$W = F\cdot \Delta s$ (1)

Where:

$F$ - Force applied by the cart, measured in newtons.

$\Delta s$ - Distance travelled by the car, measured in meters.

$W$ - Work done on the cart, measured in joules.

If we know that $F = 888\,N$ and $\Delta s = 22\,m$ , then the work done on the cart is:

$W =(888\,N)\cdot (22\,m)$

$W = 19536\,J$

19536 joules of work are done.

b) The work is done by the engine on the structure of the cart.

c) There are three options: (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.

d) If we know that $F = 1111\,N$ and $\Delta s = 22\,m$ , then the work on the cart is:

$W = (1111\,N)\cdot (22\,m)$

$W = 24442\,N$

24442 joules of work are done.

e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.

f) The gas consumption is directly proportional to the square of velocity and mass of the cart and, hence, to the work done on the cart. In consequence, we conclude that the bigger engine uses more gas to go 22 meters.

g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.

3 0

3 years ago

The Hertzsprung-Russel diagram is used to show the relationship between which two characteristics of stars?

Dahasolnce [82]

Answer:

A

Explanation:

absolute magnitude and luminosity vs the spectral position/ temperature

5 0

3 years ago

What will be the restoring force if a spring with a spring constant of 45 newtons per meter is pulled 0.03 meters in the downwar

allsm [11]

To calculate for the force in a spring, we use Hooke's Law which relates force and the displacement of the spring. It is said that the force is directly proportional to the displacement. So, it will have the equation F = kx where k is a constant and it is the spring constant.

F = kx
F = 45 N/m (0.03)
F = 1.35 N

8 0

3 years ago