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LuckyWell [14K]

2 years ago

7

An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15 m if her initial speed is 3 m/s. wh

at is the free-fall acceleration on the planet?

1 answer:

nata0808 [166]2 years ago

7 0

Answer:

R = V^2 sin 2 θ / g range formula

R is a maximum for θ = 45 and R = V^2 g

g = V^2 / R = 3^2 / 15 = .6 m/s^2

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Answer:

Explanation:

Given

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