Question

An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15 m if her initial speed is 3 m/s. what is the free-fall acceleration on the planet?

Answer 1

Answer:

R = V^2 sin 2 θ / g        range formula

R is a maximum for θ = 45 and R = V^2  g

g = V^2 / R = 3^2 / 15 = .6 m/s^2