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loris [4]
3 years ago
5

A major part of the greenhouse effect is that it involves the absorption of the earth's outgoing radiation by atmospheric gases.

along with carbon dioxide, what atmospheric component is largely responsible for this process
Physics
1 answer:
trasher [3.6K]3 years ago
7 0

A major part of the greenhouse effect is that it involves the absorption of the earth's outgoing radiation by atmospheric gases. Along with carbon dioxide, the atmospheric component that is largely responsible for this process is the water vapor.

<span>Water vapor is already the gaseous phase of water.  It evaporates all the way through the atmosphere. Since water vapor is produced from the boiling liquid of water, or from the ice sublimation, all the radiation and other chemicals that produces greenhouse gases which are present in the water will also be carried towards the Earth’s atmosphere during the process of evaporation. This, along with carbon dioxide totally damages the Earth’s ozone layer.</span>

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The sun’s gravitational attraction and the planet’s inertia keeps planets moving is circular orbits.

Explanation:

The planets in the Solar System move around the Sun in a circular orbit. This motion can be explained as a combination of two effects:

1) The gravitational attraction of the Sun. The Sun exerts a force of gravitational attraction on every planet. This force is directed towards the Sun, and its magnitude is

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M is the mass of the Sun

m is the mass of the planet

r is the distance between the Sun and the planet

This force acts as centripetal force, continuously "pulling" the planet towards the centre of its circular orbit.

2) The inertia of the planet. In fact, according to Newton's first law, an object in motion at constant velocity will continue moving at its velocity, unless acted upon an external unbalanced force. Therefore, the planet tends to continue its motion in a straight line (tangential to the circular orbit), however it turns in a circle due to the presence of the gravitational attraction of the Sun.

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8 0
3 years ago
a large sphere is on a horizontal field on a sunny day. at a certain time the shadow reaches out a distance of 10 m from the poi
Mars2501 [29]

The radius of the sphere in meters is ,r = 10\sqrt{5} -20

Think about the angle the ground and the shadow make. Since the sun's beams are parallel, the angle created by the stick's shadow is also equal. Since the stick is 1 m high and its shadow is 2 m long, we know that the stick's angle is arctan 1/2. Therefore, by thinking of a right-angled triangle,

r/10 = tan [arctan(1/2)] = tan (1/2)

Since, tan (θ/2) = 1-cos(θ) / sin(θ)

we find that,

r/10 = \sqrt{5} -2

Hence, r = 10\sqrt{5} -20

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5 0
1 year ago
Calculate the orbital speed (in m/s) of a satellite that circles the Earth with a time period of 12.00 hours. The mass of the Ea
Hoochie [10]

Answer:

v = 3869 m/s

Explanation:

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v = \sqrt{\frac{GM}{r}}

also we know that

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T = \frac{2\pi r}{v}

now from above equation we know that

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now plug in all data in this equation

v = (\frac{2\pi (6.67 \times 10^{-11})(5.97 \times 10^{24})}{12 \times 3600})^{1/3}

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3 0
3 years ago
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myrzilka [38]
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algol13

Answer

Acceleration=>10.20mm/s

Explanation

Below in image

4 0
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