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loris [4]
3 years ago
5

A major part of the greenhouse effect is that it involves the absorption of the earth's outgoing radiation by atmospheric gases.

along with carbon dioxide, what atmospheric component is largely responsible for this process
Physics
1 answer:
trasher [3.6K]3 years ago
7 0

A major part of the greenhouse effect is that it involves the absorption of the earth's outgoing radiation by atmospheric gases. Along with carbon dioxide, the atmospheric component that is largely responsible for this process is the water vapor.

<span>Water vapor is already the gaseous phase of water.  It evaporates all the way through the atmosphere. Since water vapor is produced from the boiling liquid of water, or from the ice sublimation, all the radiation and other chemicals that produces greenhouse gases which are present in the water will also be carried towards the Earth’s atmosphere during the process of evaporation. This, along with carbon dioxide totally damages the Earth’s ozone layer.</span>

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a hot piece of copper is placed in an insulated cup. what is the final temperature of the water and copper?
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Option C. 30°C.

Explanation:

The following data were obtained from the question:

Mass of water (Mw) = 0.5 Kg

Specific heat capacity of water (Cw) = 4.18 KJ/Kg°C

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22°C

Change in temperature (ΔT) = T2 – Tw1 = T2 – 22°C

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Specific heat capacity of copper (Cc) = 0.386 KJ/kg°C

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Final temperature (T2) =..?

Note: Both the water and the piece copper will have the same final temperature and the heat will be zero since the water will cool the piece of copper.

Thus, we can determine the final temperature of the water and copper as follow:

Q = MwCwΔT + McCcΔT

0 = 0.5 x 4.18 x (T2 – 22) + 0.5 x 0.386 x (T2 – 115)

0 = 2.09 (T2 – 22) + 0.193 (T2 – 115)

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2.09T2 + 0.193T2 = 45.98 + 22.195

2.283T2 = 68.175

Divide both side by the coefficient of T2 i.e 2.283

T2 = 68.175/2.283

T2 = 29.8 ≈ 30°C

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