Which of the following is an SI base unit for measuring mass?

Tom travels to the moon for NASA. While on the moon, the total weight of Tom and his lunar exploration suit is 224 N. His suit h

marissa [1.9K]

The answer is 490

Weight = mass * g

Weight on Earth = 50 * 9.81 =

490.5 ~ 490

4 0

2 years ago

Two blocks are sliding along a frictionless track. Block A (mass 4.03 kg) is moving to the right at 3.00 m/s. Block B (mass 4.84

julsineya [31]

Answer:

The total momentum of the system before the collision is 5.334 kg-m/s towards left.

Explanation:

Given that,

Mass of the block A, $m_A=4.03\ kg$

Speed of block A, $v_A=3\ m/s$

Mass of the block B, $m_B=4.8\ kg$

Mass of block B, $u_B=-3.6\ m/s$

Let p is the total momentum of the system before the collision. It is given by :

$p=m_Av_A+m_Bv_B\\\\p=4.03\times 3+4.84\times (-3.6)\\\\p=-5.334\ kg-m/s$

So, the total momentum of the system before the collision is 5.334 kg-m/s towards left. Hence, this is the required solution.

6 0

3 years ago

A man drops a rock into a well. (a) the man hears the sound of the splash 2.40 s after he releases the rock from rest. the speed

Burka [1]

Part (a)
Let h = depth of water surface from the top of the well, m

Because the stone is dropped, its initial velocity is zero.
Let t₁ = time for the stone to drop, s
Then
h = (1/2)*(9.8 m/s²)*(t₁ s)²
t₁ = √(h/4.9) s = 0.4518√h s

The velocity of sound is 336 m/s.
The time for the sound wave to travel from the water surface to the top of the well is
t₂ = h/336 m/s

Because the time before the sound is heard is 2.4 s, therefore
t₁ + t₂ = 2.4
0.45181√h + h/336 = 2.4
Multiply through by 336.
151.8082√h + h = 806.4
h - 806.4 = -151.8082√h
h² - 1612.8h + 6.5028 x 10⁵ = 2.3046 x 10⁴h
h² - 2.4659 x 10⁴h + 6.5028 x 10⁵ = 0

Solve with the quadratic formula.
h = 0.5[2.4659 x 10⁴ +/- 2.4606 x 10⁴]
= 24632 m or 26.5 m

Test the two answers.
When h = 24632,
t₁ = 0.4518√(24632) = 70.9 s (Not acceptable)
When h = 26.5 m,
t₁ = 0.4518√(26.5) = 2.3258 s, t₂ = 26.5/336 = 0.0789 s,
t₁+t₂ = 2.4 s (CORRECT)

Answer: h = 26.5 m

Part (b)
If travel time for the sound is ignored, then
0.4518√h = 2.4
h = (2.4/0.45118)² = 28.2 m
The percent error is 100*[(28.2 - 26.5)/26.5] = 6.42%

Answer: The error is 6.4%

4 0

3 years ago

A 260-kg glider is being pulled by a 1,940-kg jet along a horizontal runway with an acceleration of a= 2.20 m/s^2 to the right.

lisov135 [29]

Answer:

a) The magnitude of the thrust provided by the jet's engines is 4840 newtons.

b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.

Explanation:

a) By Newton's laws we construct the following equations of equilibrium. Please notice that both the glider and the jet experiments has the same acceleration:

Jet

$\Sigma F = F - T = m_{J}\cdot a$ (1)