Question

What is the change in internal energy of the system delta u if 82 kj of heat energy is absorbed by the system and 40 kj of work is done on the system for a certain process?

Answer 1

Answer:

The internal energy of the system is 42 J.

Explanation:

Given that,

Heat energy = 82 kJ

Work done = 40 kJ

We need to calculate the change in internal energy

Using first law of thermodynamics

$dQ=dE+(-dW)$

$dQ=dE-dW$

Where, dQ = change in internal energy

dW= Work done

dE= Heat energy

Put the value into the formula

$dQ=82-40$

$dQ=42\ J$

Hence, The internal energy of the system is 42 J.