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marishachu [46]
2 years ago
11

The percentage of organ donors who died from drug overdoses changed by 9.34% - 1.10% =8.24% between 2000 and 2015. what is this

as a percentage of donors dying from drug overdoses in 2000?
Mathematics
1 answer:
larisa86 [58]2 years ago
5 0

The current percentage in comparison to in the year 2000 is 88.22%.

We are given the percentage of death in the year 2000, 2015 and the difference. Now, we have to find the percentage of donors between change and the original deaths in the year 2000.

To find this, we will use the following formula -

Percentage change = Difference between the percentage change in the year 2000 to 2015 ÷ Percentage of deaths in the year 2000 ×100

Now, keep the values in formula to find the percentage change.

Percentage change = \frac{8.24}{9.34} *100

Performing division to find the percentage change

Percentage change = 0.882*100

Further performing multiplication to get the answer in the form of percentage

Percentage change = 88.22%

Hence, the comparison of difference with the percentage of donors dying from drug overdoses in 2000 is 88.22%.

Learn more about problems on percentage -

brainly.com/question/11712455

#SPJ4

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Plz help me with 13-16
svetlana [45]

Answer:

13) x = 10

14) x = 22

15) x = 12

16) x = -15

Step-by-step explanation:

13) 4x+5x=9x;90/9=10

14) 45-1=44;44/2=22

15) 37-1=36;36/3=12

16) -54+26=-28;x-28=3x+2;x=-15

6 0
3 years ago
If AB=BC,AB=4=4x-2,andBC=3x+3,fine the length of AB
laila [671]

Answer:

18

Step-by-step explanation:

First, I'm assuming AB=4=4x-2 was a typo and it's supposed to be AB = 4x - 2

AB=BC

AB = 4x - 2 BC = 3x + 3

4x - 2 = 3x + 3

Solve for x Add 2 to each side

4x - 2 = 3x + 3

4x - 2 + 2 = 3x + 3 + 2

4x = 3x + 5 Subtract 3x from each side.

4x - 3x = 3x- 3x + 5

4x - 3x = 5

x = 5

Now plug back in to the original equations

AB = 4x - 2                  BC = 3x + 3

AB = 4 (5) - 2               BC = 3(5) + 3

AB = 20 - 2                  BC = 15 + 3

AB = 18                        BC = 18

So AB is 18

3 0
3 years ago
Sec s = 1.6948
Anastaziya [24]
That'd be true only if the value of "s" is the exact same one for both
namely  if sec(s) = cos(s)
then solving for "s"
thus

\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\\\
thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s)
\\\\\\
\pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides}
\\\\\\
cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s
5 0
3 years ago
Consider the functions:
jolli1 [7]
The x and y axis so that’s why it’s true
5 0
3 years ago
Read 2 more answers
8 pts
kolbaska11 [484]

Answer:

6 cm.

Step-by-step explanation:

Since they've given use the area of the triangle, we can use the area formula to find the base of the triangle.

The formula to find the area of a triangle is:

a= 1/2hb

h = height

b= base

We know:

a=24

h=8

7 0
2 years ago
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