Ask question

Ask question

All categories

marishachu [46]

2 years ago

11

The percentage of organ donors who died from drug overdoses changed by 9.34% - 1.10% =8.24% between 2000 and 2015. what is this

as a percentage of donors dying from drug overdoses in 2000?

1 answer:

larisa86 [58]2 years ago

5 0

The current percentage in comparison to in the year 2000 is 88.22%.

We are given the percentage of death in the year 2000, 2015 and the difference. Now, we have to find the percentage of donors between change and the original deaths in the year 2000.

To find this, we will use the following formula -

Percentage change = Difference between the percentage change in the year 2000 to 2015 ÷ Percentage of deaths in the year 2000 ×100

Now, keep the values in formula to find the percentage change.

Percentage change = $\frac{8.24}{9.34} *100$

Performing division to find the percentage change

Percentage change = 0.882*100

Further performing multiplication to get the answer in the form of percentage

Percentage change = 88.22%

Hence, the comparison of difference with the percentage of donors dying from drug overdoses in 2000 is 88.22%.

Learn more about problems on percentage -

brainly.com/question/11712455

#SPJ4

You might be interested in

at a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. Th

VladimirAG [237]

Answer:

The number of tickets sold to the public was 375

Step-by-step explanation:

<u><em>The complete question is</em></u>

At a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. The students paid $15 and public $25. When all the tickets were sold, $10,500 was collected. How many tickets were sold to the public?

Let

x ----> number of tickets sold to the students

y ----> number of tickets sold to the public

we know that

$x+y=450$ ----> equation A

$15x+25y=10,500$ ----> equation B

Solve the system by graphing

The solution is the intersection point both graphs

using a graphing tool

The solution is the point (75,375)

see the attached figure

therefore

The number of tickets sold to the public was 375

6 0

4 years ago

2,17,82,257,626,1297 next one please ?

In-s [12.5K]

The easy thing to do is notice that 1^4 = 1, 2^4 = 16, 3^4 = 81, and so on, so the sequence follows the rule $n^4+1$ . The next number would then be fourth power of 7 plus 1, or 2402.

And the harder way: Denote the <em>n</em>-th term in this sequence by $a_n$ , and denote the given sequence by $\{a_n\}_{n\ge1}$ .

Let $b_n$ denote the <em>n</em>-th term in the sequence of forward differences of $\{a_n\}$ , defined by

$b_n=a_{n+1}-a_n$

for <em>n</em> ≥ 1. That is, $\{b_n\}$ is the sequence with

$b_1=a_2-a_1=17-2=15$

$b_2=a_3-a_2=82-17=65$

$b_3=a_4-a_3=175$

$b_4=a_5-a_4=369$

$b_5=a_6-a_5=671$

and so on.

Next, let $c_n$ denote the <em>n</em>-th term of the differences of $\{b_n\}$ , i.e. for <em>n</em> ≥ 1,

$c_n=b_{n+1}-b_n$

so that

$c_1=b_2-b_1=65-15=50$

$c_2=110$

$c_3=194$

$c_4=302$

etc.

Again: let $d_n$ denote the <em>n</em>-th difference of $\{c_n\}$ :

$d_n=c_{n+1}-c_n$

$d_1=c_2-c_1=60$

$d_2=84$

$d_3=108$

etc.

One more time: let $e_n$ denote the <em>n</em>-th difference of $\{d_n\}$ :

$e_n=d_{n+1}-d_n$

$e_1=d_2-d_1=24$

$e_2=24$

etc.

The fact that these last differences are constant is a good sign that $e_n=24$ for all <em>n</em> ≥ 1. Assuming this, we would see that $\{d_n\}$ is an arithmetic sequence given recursively by

$\begin{cases}d_1=60\\d_{n+1}=d_n+24&\text{for }n>1\end{cases}$

and we can easily find the explicit rule:

$d_2=d_1+24$

$d_3=d_2+24=d_1+24\cdot2$

$d_4=d_3+24=d_1+24\cdot3$

and so on, up to

$d_n=d_1+24(n-1)$

$d_n=24n+36$

Use the same strategy to find a closed form for $\{c_n\}$ , then for $\{b_n\}$ , and finally $\{a_n\}$ .

$\begin{cases}c_1=50\\c_{n+1}=c_n+24n+36&\text{for }n>1\end{cases}$

$c_2=c_1+24\cdot1+36$

$c_3=c_2+24\cdot2+36=c_1+24(1+2)+36\cdot2$

$c_4=c_3+24\cdot3+36=c_1+24(1+2+3)+36\cdot3$

and so on, up to

$c_n=c_1+24(1+2+3+\cdots+(n-1))+36(n-1)$

Recall the formula for the sum of consecutive integers:

$1+2+3+\cdots+n=\displaystyle\sum_{k=1}^nk=\frac{n(n+1)}2$

$\implies c_n=c_1+\dfrac{24(n-1)n}2+36(n-1)$

$\implies c_n=12n^2+24n+14$

$\begin{cases}b_1=15\\b_{n+1}=b_n+12n^2+24n+14&\text{for }n>1\end{cases}$

$b_2=b_1+12\cdot1^2+24\cdot1+14$

$b_3=b_2+12\cdot2^2+24\cdot2+14=b_1+12(1^2+2^2)+24(1+2)+14\cdot2$

$b_4=b_3+12\cdot3^2+24\cdot3+14=b_1+12(1^2+2^2+3^2)+24(1+2+3)+14\cdot3$

and so on, up to

$b_n=b_1+12(1^2+2^2+3^2+\cdots+(n-1)^2)+24(1+2+3+\cdots+(n-1))+14(n-1)$

Recall the formula for the sum of squares of consecutive integers:

$1^2+2^2+3^2+\cdots+n^2=\displaystyle\sum_{k=1}^nk^2=\frac{n(n+1)(2n+1)}6$

$\implies b_n=15+\dfrac{12(n-1)n(2(n-1)+1)}6+\dfrac{24(n-1)n}2+14(n-1)$

$\implies b_n=4n^3+6n^2+4n+1$

$\begin{cases}a_1=2\\a_{n+1}=a_n+4n^3+6n^2+4n+1&\text{for }n>1\end{cases}$

$a_2=a_1+4\cdot1^3+6\cdot1^2+4\cdot1+1$

$a_3=a_2+4(1^3+2^3)+6(1^2+2^2)+4(1+2)+1\cdot2$

$a_4=a_3+4(1^3+2^3+3^3)+6(1^2+2^2+3^2)+4(1+2+3)+1\cdot3$

$\implies a_n=a_1+4\displaystyle\sum_{k=1}^3k^3+6\sum_{k=1}^3k^2+4\sum_{k=1}^3k+\sum_{k=1}^{n-1}1$

$\displaystyle\sum_{k=1}^nk^3=\frac{n^2(n+1)^2}4$

$\implies a_n=2+\dfrac{4(n-1)^2n^2}4+\dfrac{6(n-1)n(2n)}6+\dfrac{4(n-1)n}2+(n-1)$

$\implies a_n=n^4+1$

4 0

3 years ago

Will mark you as brainliest for the correct answer!

Alexandra [31]

Answer:

mean= 5+10+15+20+25+30/6=20.82=21

fraction=2+9/24=11/24

3 0

3 years ago

A penguin walks 10 feet in 6 seconds. At this speed:

frutty [35]

Answer: The penguin will walk 75.15 feet in 45 sec

3 0

3 years ago

Read 2 more answers

Calculate the value of (-8) * (-2/3)

topjm [15]

Answer: Exact Form: 16/3

Decimal Form: 5.3333...

Mixed Number form: 51/3

Step-by-step explanation: Hope I helped

6 0

3 years ago

Read 2 more answers