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givi [52]
3 years ago
7

What is y-2=-2(x-3) In slope intercept form

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

y=-2x+8

Step-by-step explanation:

distribute:

y-2=-2x+6

add 2:

y=-2x+8

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One side times the side different from the first one =area
insens350 [35]
Length × width=area
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What is the probability of rolling a number greater than or equal to 8 with the sum of two dice, given that at least one of the
amid [387]

Answer:

a dice goes from 1-6

6+1=7

6+2=8

6+3=9

6+4=10

6+5=11

6+6=12

Of those possible choices, 5 are greater than or equal to 8. So the answer is 5/6.

mark brainiest please

7 0
3 years ago
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What is the volume of the composite figure. I said 36 but it is wrong.
scZoUnD [109]

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108

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6 0
3 years ago
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Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
3/12 1/6 and 1/3 same denominator
iogann1982 [59]
Yes because if you turn 6 and three to 12 then you have 2/12 and 4/12!
5 0
3 years ago
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