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stiks02 [169]
2 years ago
14

A 15. 0 ampere current flows through a 4. 75 m section of wire, perpendicular to a 0. 250 t magnetic field. what is the magnitud

e of the force exerted by the field on the wire section?
Physics
1 answer:
IgorC [24]2 years ago
3 0

Answer:

Approximately 17.8\; {\rm L}.

Explanation:

Consider a straight wire section of length L carrying a current of I. If that wire is placed in a magnetic field of strength B at an angle of \theta relative to the field, the magnitude of the magnetic force on this wire would be:

F = B\, I\, L\, \sin(\theta).

In this question, \theta = 90^{\circ} since the wire is perpendicular to the magnetic field. The magnitude of the magnetic force on this wire would be:

\begin{aligned}F &= B\, I\, L\, \sin(\theta) \\ &= (0.250\; {\rm T}) \, (15.0\; {\rm A}) \, (4.75\; {\rm m})\, (\sin(90^{\circ}) \\ &\approx 17.8\; {\rm N} \end{aligned}.

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