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abruzzese [7]
4 years ago
6

A particle is being accelerated through space by a 10 N force. Suddenly the particle encounters a second of 10 N force in the op

posite direction. The particle with both forces acting?
Physics
1 answer:
Lyrx [107]4 years ago
7 0

Answer:

The particle will be rendered still

Explanation:

The particle will be rendered still because of the Newton’s 1st law of motion states that a body will continue to move on forever until contacted by an equal and opposite force. The same case has been produced here and it is justifying the law. If the Force has another direction and magnitude than 10 N then the body will continue to move on in the direction of the greater force.

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What makes plants the beginning of the food chain?
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The answer to your question is A





7 0
3 years ago
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A ball is dropped from a height h and falls the last half of its distance in 4 seconds. How long does the ball fall? From what h
dlinn [17]

Answer:

How long does the ball fall is t_2 =  13.66 (s).

From what height is the ball originally dropped is h=  913.90 (m).

Explanation:

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3 years ago
If a person whirls an object horizontally in a counter clockwise direction and the string breaks at point P as shown, what path
Nata [24]

when an object is revolving in circular path then its velocity is always along the tangent of the circular path

so while moving in circular path if the string is break then due to law of inertia the object will always move in the direction of initial motion

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4 years ago
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If two balls have the same volume,
Lena [83]

Here, we are required to find the relationship between balls of different mass(a measure of weight) and different volumes.

  • 1. Ball A will have the greater density
  • 2. Ball C and Ball D have the same density.
  • 3. Ball Q will have the greater density.
  • 4. Ball X and Y will have the same density

The density of an object is given as its mass per unit volume of the object.

Mathematically;.

  • Density = Mass/Volume.

For Case 1:

  • Va = Vb and Ma = 2Mb
  • D(b) = (Mb)/(Vb) and D(a) = 2(Mb)/Vb
  • Therefore, the density of ball A,
  • D(a) = 2D(b).
  • Therefore, ball A has the greater density.

For Case 2:

  • Vc = 3Vd,

  • Vd = (1/3)Vc

  • Md = (1/3)Mc

  • D(c) = (Mc)/(Vc) and D(d) = (1/3)Md/(1/3)Vd

  • D(c) = D(d).

  • Therefore, ball C and D have the same density

For Case 3:

  • Vp = 2Vq and Mp = Mq
  • D(p) = (Mq)/2(Vq) and D(q) = (Mq)/Vq
  • Therefore, the density of ball P is half the density of ball Q
  • Therefore, ball Q has the greater density.

For case 4:

  • Mx = (1/2)My
  • Vx = Vy

Therefore, Ball X and Ball Y have the same density.

Read more:

brainly.com/question/18110802

8 0
3 years ago
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