Average velocity = Total Displacement / Total time taken
Total displacement is the distance from starting to end point.
35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.
So displacement =
= 96.56 km
So, Total displacement = 96.56 km
So, Average Velocity = 96.56 / 2 = 48.28 km/hr
Answer:
1.08×10⁹ J
Explanation:
From the question given above, the following data were obtained:
Power (P) = 100 kilowatt
Time (t) = 3 hours
Energy (E) =?
Next, we shall convert 100 kilowatt to Watts. This can be obtained as follow:
1 KW = 1000 W
Therefore,
100 KW = 100 KW × 1000 W / 1 KW
100 KW = 100000 W
Thus, 100 KW is equivalent to 100000 W.
Next, we shall convert 3 hrs to second (s). This can be obtained as follow:
1 h = 3600 s
Therefore,
3 h = 3 h × 3600 s / 1 h
3 h = 10800 s
Thus, 3 h is equivalent to 10800 s.
Finally, we shall determine the amount of energy consumed as follow:
Power (P) = 100000 W
Time (t) = 10800 s
Energy (E) =?
P = E/t
100000 = E / 10800
Cross multiply
E = 100000 × 10800
E = 1.08×10⁹ J
Therefore, 1.08×10⁹ J of energy was consumed.
let here North direction is along +Y and South direction is along -Y
similarly East direction is towards +X and west direction is towards -X
now it is given that
first it moves 235 km north
then it moves back 126 km south
then again he moves north
now the total displacement is given as
so final displacement of train is 154 km North
We can find the x-component of the force vector, so Fx = 25N(cos30). Then, we can sub this into the work equation W = Fs or W = Fd.
Therefore, W = (25N(cos30))(3m) = 64.95 J.
With sig figs, it is 60 J.
